All categories

3 years ago

Please help :) it’s my last j-lab question and I have to get a 100.

Mathematics

1 answer:

algol133 years ago

5 0

Answer:

The answer would be the bottom left, sorry I don't know what letter that is.

Step-by-step explanation:

You might be interested in

B. If Café Mocha charges $1.98 for each cup of coffee, how

dimaraw [331]

Answer:

Hi! I really love ur work and hope it goes well. I wanted to order a custom cake for my parents anniversary and it's there 18 years together happily ❤. I wanted a custom cake and the I want i

4 0

2 years ago

$15.00 divided by 4 = ?

GenaCL600 [577]

Answer: 3.75

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

If i started a business making braclets for $2 and necklaces for $3 with a budget >200 what would be the inequality equation?

kupik [55]

If i started a business making braclets for $2 and necklaces for $3 with a budget >200 what would be the inequality equation?
How would I graph

Solution:
let x= number of bracelets
y= number of necklaces

Thus, the equation would be:
$2x+$3y>200

In graphing this equation, you just have to substitute any number for the values of x and y as long as when substituted, their sum is greater than 200

8 0

3 years ago

A student downloaded a new game on her phone that was recommended by her friend. She wanted to show her friend how good

anygoal [31]

Answer:

a. 587

b. 543

Step-by-step explanation:

a. Mean = sum / number of numbers

To find the sum, we can add the numbers up.

432 + 543 + 348 + 788 + 823 = 2934

There are 5 numbers. Our mean is thus

2934/5 = 586.8, or 587 when rounding up. We round up because we have a .8 at the end, and 8 ≥ 5

b. To find the median, we first must order the numbers. The numbers ordered are this:

348 , 432 , 543 , 788 , 823

To find the median, we can cross off one number on each side until we are left with one or two numbers.

348 , 432 , 543 , 788 , 823

cross out one number from each endpoint

432 , 543 , 788

cross out one number from each endpoint

543

7 0

2 years ago

PLEASE!!!!!!!The adjoining figure shows two circles with the same center. The

Nookie1986 [14]

<h3>Answer:</h3>

$\boxed{\boxed{\pink{\sf \leadsto Hence \ the \ area \ of \ shaded \ region \ is 264 cm^2}}}$

<h3>Step-by-step explanation:</h3>

Here , two circles are given which are concentric. The radius of larger circle is 10cm and that of smaller circle is 4cm . And we need to find thelarea of shaded region.

From the figure it's clear that the area of shaded region will be the difference of areas of two circles.

Let the,

Radius of smaller circle be r .
Radius of smaller circle be r .
Area of shaded region be $\bf Area_{shaded}$

$\bf \implies Area_{Shaded}= Area_{bigger}-Area_{smaller} \\\\\bf\implies Area_{Shaded} = \pi R^2 - \pi r^2 \\\\\bf\implies Area_{shaded} = \pi ( R^2-r^2) \\\\\bf\implies Area_{shaded} = \pi [ (10cm)^2 - (4cm)^2] \\\\\bf\implies Area_{shaded} = \pi [ 100cm^2-16cm^2] \\\\\bf\implies Area_{shaded} = \pi \times 84cm^2 \\\\\bf\implies Area_{shaded} = \dfrac{22}{7}\times 84cm^2 \\\\\bf\implies \boxed{\red{\bf Area_{shaded} = 264 cm^2 }}$

<h3>Hence the area of the shaded region is 264 cm².</h3>

5 0

2 years ago