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wolverine [178]
2 years ago
8

Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade

of B equals .30. The probability that a randomly selected student from this class will receive either an A or a B equals:________
a. 0.09
b. 9
c. 6
d. 3
Mathematics
1 answer:
Misha Larkins [42]2 years ago
8 0

Answer:

c. 0.6

Step-by-step explanation:

A student cannot receive an A or a B simultaneously, so P(A \cap B) = 0.

Grade of A equals .30 and the probability of receiving a grade of B equals .30.

This means that P(A) = P(B) = 0.3

The probability that a randomly selected student from this class will receive either an A or a B equals:

This is:

P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.3 + 0.3 - 0 = 0.6

So the probability is 0.6, and the correct answer is given by option c.

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Answer:

P(X=7)

And using the probability mass function we got:

P(X=7)=(15C7)(0.23)^7 (1-0.23)^{15-7}=0.0271  

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:  

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The probability mass function for the Binomial distribution is given as:  

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Where (nCx) means combinatory and it's given by this formula:  

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And we want to find the following probability:

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And using the probability mass function we got:

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