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wolverine [178]
3 years ago
8

Assume that in a statistics class the probability of receiving a grade of A equals .30 and the probability of receiving a grade

of B equals .30. The probability that a randomly selected student from this class will receive either an A or a B equals:________
a. 0.09
b. 9
c. 6
d. 3
Mathematics
1 answer:
Misha Larkins [42]3 years ago
8 0

Answer:

c. 0.6

Step-by-step explanation:

A student cannot receive an A or a B simultaneously, so P(A \cap B) = 0.

Grade of A equals .30 and the probability of receiving a grade of B equals .30.

This means that P(A) = P(B) = 0.3

The probability that a randomly selected student from this class will receive either an A or a B equals:

This is:

P(A \cup B) = P(A) + P(B) - P(A \cap B) = 0.3 + 0.3 - 0 = 0.6

So the probability is 0.6, and the correct answer is given by option c.

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Find the area of the figure. Use 3.14 for pie . Round your answer to the nearest tenth.
gizmo_the_mogwai [7]

Answer:

538.3

Step-by-step explanation:

First of all find the area of the rectangle

L*W

15*30

450

Now find the area of semi circle

1/2\pi r^{2}

Since radius is half a diameter divided 15 by 2=7.5

1/2\pi 7.5^{2}                            7.5 times 7.5= 56.25

1/2*3.14*56.25

56 times 3.14 is 176.625 now multiply 176.625 by 1/2

Answer is 88.3125

Now add 450 to 88.3125

Final answer: 538.3125

7 0
3 years ago
A rectangular prism has a length of 312 in., a width of 5 in., and a height of 112 in.
Soloha48 [4]
Multiply the dimensions to get 174,720 in^3
6 0
4 years ago
Read 2 more answers
Simplify the polynomial (−8x) x (−2x)
harkovskaia [24]
Negative multiplied by a negative is positive
8 multiplied by 2 is 16 
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combine them all up and you get ......
16 x^{2} is the answer :-)
4 0
3 years ago
How to solve this question #4 ?
gayaneshka [121]
This question is a piece-o-cake if you know the formulas for the area and volume of a sphere, and impossible of you don't.

Area of a sphere = 4 π R²  (just happens to be the area of 4 great circles)

Volume of a sphere = (4/3) π R³

We know the area of this sphere's great circle, so we can use the
first formula to find the sphere's radius.  Then, once we know the
radius, we can use the second formula to find its volume.

Area of 4 great circles = 4 π R²

Area of ONE great circle = π R²

           225 π cm²  =  π R²

               R²  =  225 cm²

               R  =  √225cm²  =  15 cm .

Now we have a number for R, so off we go to the formula for volume.

         Volume  =  (4/3) π R³

                      =  (4/3) π (15 cm)³

                      =  (4/3) π (3,375 cm³)

                       =      14,137.17  cm³      (rounded)

This answer feels very good UNTIL you look at the choices.
_____________________________________________________

I've gone around several loops and twists trying to find out what gives here,
but have come up dry.

The only thing I found is the possibility of a misprint in the question:  

If the area of a great circle is 225π cm², then the sphere's AREA is 900π cm².

I'm sure this is not the discrepancy.  I'll leave my solution here, and hope
someone else can find why I'm so mismatched with the choices.
5 0
4 years ago
Read 2 more answers
Match the following:a. When two variables change in the same direction, one remaining larger than the other by the same factor b
Margarita [4]

Answer:

a. When two variables change in the same direction, one remaining larger than the other by the same factor - direct relationship

b. To insert between neighboring points or estimate by taking an average of known values - interpolate

c. A relationship between two variables in which the product remains constant. When one variable increases the other decreases in proportion so that the product is unchanged - inverse relationship

5 0
3 years ago
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