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Nataly_w [17]
3 years ago
5

What is the equation of the line with (1,0) and (6,6)?

Mathematics
1 answer:
ch4aika [34]3 years ago
7 0

Answer:

  6x -5y = 6

Step-by-step explanation:

You can use the 2-point form of the equation of a line to find it.

  y = (y2 -y1)/(x2 -x1)(x -x1) +y1

  y = (6-0)/(6-1)(x -1) +0

  y = 6/5(x -1) . . . . . . point-slope form

  y = (6/5)x -6/5 . . . . slope-intercept form

  5y = 6x -6

  6x -5y = 6 . . . . . . . standard form

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Step-by-step explanation:

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Which equation could be used to find the length of the hypotenuse?
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The first option .

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monitta

340 in 0.75 hours. Divide both sides by 0.75, therefore 340/0.75 in 0.75/0.75 hour.
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3 years ago
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Prove the following by induction. In each case, n is apositive integer.<br> 2^n ≤ 2^n+1 - 2^n-1 -1.
frutty [35]
<h2>Answer with explanation:</h2>

We are asked to prove by the method of mathematical induction that:

2^n\leq 2^{n+1}-2^{n-1}-1

where n is a positive integer.

  • Let us take n=1

then we have:

2^1\leq 2^{1+1}-2^{1-1}-1\\\\i.e.\\\\2\leq 2^2-2^{0}-1\\\\i.e.\\2\leq 4-1-1\\\\i.e.\\\\2\leq 4-2\\\\i.e.\\\\2\leq 2

Hence, the result is true for n=1.

  • Let us assume that the result is true for n=k

i.e.

2^k\leq 2^{k+1}-2^{k-1}-1

  • Now, we have to prove the result for n=k+1

i.e.

<u>To prove:</u>  2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Let us take n=k+1

Hence, we have:

2^{k+1}=2^k\cdot 2\\\\i.e.\\\\2^{k+1}\leq 2\cdot (2^{k+1}-2^{k-1}-1)

( Since, the result was true for n=k )

Hence, we have:

2^{k+1}\leq 2^{k+1}\cdot 2-2^{k-1}\cdot 2-2\cdot 1\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{k-1+1}-2\\\\i.e.\\\\2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-2

Also, we know that:

-2

(

Since, for n=k+1 being a positive integer we have:

2^{(k+1)+1}-2^{(k+1)-1}>0  )

Hence, we have finally,

2^{k+1}\leq 2^{(k+1)+1}-2^{(k+1)-1}-1

Hence, the result holds true for n=k+1

Hence, we may infer that the result is true for all n belonging to positive integer.

i.e.

2^n\leq 2^{n+1}-2^{n-1}-1  where n is a positive integer.

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3 years ago
Need help on this problem
trasher [3.6K]
The answer to the question

3 0
3 years ago
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