One question at a time, please. I will focus on #16 and ignore #18.
slope: 3/4 line passes thru (-8,2)
Write out y = mx + b. Subst. 2 for y. Subst. -8 for x Subst. (3/4) for m:
2 = (3/4)(-8) + b. Find b. 2 = -6 + b => b = 8
So your equation is y = (3/4)x + 8. Please, use ( ) around those fractions!
Your original perimeter is 32cm. 3/2 is equal to 1.5. 32x1.5= 48 cm perimeter
Answer:
Step-by-step explanation:
Remark
Simple answer: you can't. I mean that you can't try to use 4 numbers, but you can solve the problem. You are going to have to redraw the diagram on another sheet of paper. Follow the directions below.
Directions for diagram extension.
Go to the right hand end of the 10 unit line.
Draw a line from the intersection point of the 10 unit line and 12 unit line
Draw this line so it is perpendicular to the 18 unit line. That will mean that the new line is parallel (and equal) to x
Mark the intersect point of the new line and the 18 unit line as B
Mark the intersect point of the 18 point line and the 12 unit line as C
Given and constructed
BC = 18 - 10 = 8
BC is one leg of the Pythagorean triangle.
The new x is the other leg of the Pythagorean triangle.
12 is the hypotenuse.
Formula
x^2 + 8^2 = 12^2
x refers to the new x which is equal to the given x
Solution
x^2 + 64 = 144 Subtract 64 from both sides
x^2 +64 - 64 = 144-64 Combine
x^2 = 80 Break 80 down.
x^2 = 4 * 4 * 5 Take the square root of both sides
x = 4*sqrt(5)
Comment
If you want the area it is 4*sqrt(5)(10 + 18)/2 = 56*sqrt(5)
Given P is T, q is F and r is F.
Let us find p ↔ q first.
↔ is called bi-conditional operator and is true when p and q both are matched.
Since here p is T and q is F, p↔q is F. ( Since p and q are not matching)
~p v r = ~T v F = F v F = F
Hence (p↔q)→(~pvr) = F → F = T (Since conditional operator → is false if and if first proposition is T and second proposition is F, for all other values it is T)
The answer is the third option (2 square root 22)
