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Lerok [7]
3 years ago
14

Question 24

Mathematics
1 answer:
Liula [17]3 years ago
3 0
Is there a photo? Or anything
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Answer:

23 tallys all you need to do (form what i was taught ) is add up all the tallys

b

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PLS HELP!
polet [3.4K]

Answer:

  B.) y=csc x

Step-by-step explanation:

The cosecant function has a minimum magnitude of 1, so its range excludes any values in the range -1 < y < 1.

  y = csc(x) . . . has a range that does not include -0.8

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If the mean of the data set shown below is 11, find x.<br> x, 12, 8, 15
Tems11 [23]
The answer to this problem is nine.
6 0
3 years ago
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Write the equation of the line that passes through the given points.<br> (0.-6) and (7.0)
ahrayia [7]
<h2>Answer:    y =  ⁶/₇ ( x  -  7 )</h2>

Step-by-step explanation:

The slope of tghe line (m) = (y₂ - y₁) ÷ (x₂ - x₁)

                                          =  (- 6 -0) ÷ ( 0 - 7)

                                          =    ⁶/₇

We can now use the point-slope form to write the equation for this line:

y - y₁ = m(x - x₁) where (x₁ , y₁) = (7 , 0)

              y =  ⁶/₇ ( x  -  7 )

6 0
3 years ago
Can someone please explain how to do this.
lutik1710 [3]
Set the to equal:

x^2 - 4x+4 = 2x-4
 solve for X

subtract 2x from each side:
x^2 -6x + 4 = -4

subtract 4 from each side:

x^2 -6x = -8

add 8 to both sides:

x^2 -6x +8 = 0

factor the polynomial:

x = 4 and x = 2

using the line equation replace x with 2 and 4 and solve for y

y = 2(2) - 4 = 0
y = 2(4)-4 = 4

so the 2 points the line  crosses the curve is (2,0) and (4,4)

using those 2 points you can calculate the length:
 distance = sqrt((x2-x1)^2 +(y2-y1)^2

distance = sqrt( (4-2)^2 + (4-0)^2)

distance = sqrt (2^2 + 4^2)
 distance = sqrt (4+16)
= sqrt 20 
= 2 sqrt(5)  EXACT LENGTH


4 0
3 years ago
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