PLS ANSWER
1 answer:
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Answer:
No, it isn't.
Step-by-step explanation:
We have and let
be the subset of
of all points on the line
We need to find if is a subspace of the vector space
.
In all the possibilities for own subspace of the vector space
are :
itself.
- The vector
- All lines in
)
We know that is the subset of
of all points on the line
If we look at the equation, the point doesn't verify it because :
Which is an absurd. Therefore, doesn't contain the origin (and
is a line in
). Finally, it can't be a vector space of
Answer:
THE CORRECT OPTION IS A) Δ ABC Δ BDC
Δ ADB
Step-by-step explanation:
The first option is in correct order of triangle ,we can easily the their sides are proportionate . And having eqal angles.