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Oksana_A [137]
4 years ago
7

What is cotangent of 0

Mathematics
1 answer:
nignag [31]4 years ago
7 0
The cotangent of 0 is undefined
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Determine the axis of symmetry and the vertex of the given function. y = 2x2 − 12x + 21 Axis of symmetry:
grigory [225]

Answer:

Equation of the axis of symmetry is:   x = 3

Step-by-step explanation:

The equation

y=2x^2-12x+21

is the equation of a parabola, of the form

y=ax^2+bx+c    whose vertex is located at the x-coordinate:

x_{vertex}=\frac{-b}{2\,a}

Then, for our case the x position of the given parabola, is:

x_{vertex}=\frac{-b}{2\,a} \\x_{vertex}=\frac{12}{2\,(2)} \\x_{vertex}=3

Then the equation of the axis of symmetry, which is a vertical line that goes through the vertex, would be given by:

x = 3

8 0
3 years ago
Could someone help me
Mekhanik [1.2K]

Answer:

the third one and the last one is correct

Step-by-step explanation:

we already know the second one is wrong because of it's set up.

just replace the points (-1,7) into each equation. if it doesn't work then move on to the next one. if it does work, then use that same equation except this time to the coordinates (2,4)

5 0
3 years ago
Evaluate using the order of operations <br> 43 - 7 x 2
Semmy [17]

Answer:

29

Step-by-step explanation:

6 0
3 years ago
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How do you find the slope intercept form of an equation?
Komok [63]

Answer:

The equation of line can be written as,

y = mx + c

where, m is slope

and c is intercept of line.

Now, Suppose we have equation: ax + by + c = 0

So, transforming the given equation in above standard equation.

⇒ by = -ax - c

⇒ y = \frac{-a}{b}x +\frac{-c}{a}

Now comparing this equation with standard equation. We get,

 m =\frac{-a}{b}

and c = \frac{-c}{a}

Hence, Intercept =  c =\frac{-c}{a} for line ax + by + c = 0.

3 0
4 years ago
Complete the square to re-write the quadratic function vertex form:<br>y=x2 + 4x + 4​
ankoles [38]

Answer:

Step-by-step explanation:

y=x²+4x+4

or y=(x+2)²

or y=(x+2)²+0

vertex Is (-2,0)

3 0
3 years ago
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