Question

Water boils at different temperatures at different elevations. The boiling temperature of water is 212 degrees * F sea level (0 feet ) but drops about 1.72 degrees * F for every 1,000 feet of elevation. Write a formula for the boiling point at a given elevation. Then solve the formula for the elevation when the boiling point for water is 190 degrees F.

Answer 1

Answer:

The elevation when the boiling point of water is $190$ °$F$ is 12790.70 feet

Step-by-step explanation:

Let every 1,000 feet of elevation be $x$. Hence, we can write

$T = 212$ $- 1.72x$

Where $T$ is the boiling temperature of water at different elevations

Now, to the determine the elevation when the boiling point of water is $190$ °$F$.

We will determine $x$ by putting $T = 190$ °$F$.

Hence,

$T = 212$ $- 1.72x$

$190$  $= 212$  $- 1.72x$

$190 - 212$    $= - 1.72x$

$- 22$  $= - 1.72x$

$22 = 1.72x\\x = \frac{22}{1.72} \\x = 12.79070$

Since $x$ represents every 1,000 feet of elevation, then the elevation when the boiling point of water is $190$ °$F$

$12.79070$ × $1000$ $= 12790.70$ feet

Hence,  the elevation when the boiling point of water is $190$ °$F$ is 12790.70 feet