Answer:
<h2>12) There are 534 students who do not lunch in school.</h2>
Step-by-step explanation:
<h3>12. </h3><h3>Simple solution: </h3><h3>890 ÷ 5 = 178 </h3><h3>Therefore: 1/5 = 178 </h3><h3 /><h3>•To find the 2/5 of the students, we have to multiply 178 by 2</h3><h3>178 × 2 = 356</h3><h3>Therefore, 356 students stay to have lunch.</h3><h3 /><h3>•To find the remaining students who do not lunch in school, we have to subtract 356 to 890.</h3><h3>890 - 356 = 534</h3><h3>Therefore, there are 534 students who do not lunch in school.</h3><h3 /><h3 />
Step-by-step explanation:
The expressions are not properly written
Given
RS = 4x – 9
ST = 19
RT = 8x – 14
Based on the given parameters, the addition postulate below is true
RS+ST = RT
Substitute
4x-9+19 = 8x-14
collect like terms
4x-8x = -14-19+9
-4x = -33+9
-4x = -24
x = -24/-4
x = 6
Get RS:
RS = 4x-9
RS = 4(6)- 9
RS = 24-9
RS = 15
Get RT:
RT = 8x - 14
RT = 8(6)-14
RT = 48-14
RT = 34
I'm thinking this is what the problem looks like:

. The first thing to do is to move the

over to the other side because it has a common denominator with the other side. Doing that and at the same time combining them over their common denominator looks like this:

. The best way to solve for x now is to cross-multiply to get 3(4-x)=-4(x-4). Distributing through the parenthesis is 12 - 3x = -4x + 16. Solving for x gives us x = 4. Of course when we sub a 4 back in for x we get real problems, don't we? Dividing by zero breaks every rule in math that there ever was! So, yes, the solution is extraneous.
Answer:
f = 48/5
Step-by-step explanation:
5f = 12 * 4
5f = 48
f = 48/5