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aliya0001 [1]
4 years ago
13

There are 1,657 souvenir paperweights that need to be packed in boxes. Each box will hold 17

Mathematics
1 answer:
blondinia [14]4 years ago
4 0

Answer:

Therefore we can say that 98 boxes will be needed to hold all the paperweights.

Step-by-step explanation:

i) there are 1657 souvenir paperweights that need to be packed in boxes.

ii) each box will hold 17 paperweights

iii) therefore the number of boxes that will be needed are

   = \dfrac{total\hspace{0.15cm} number\hspace{0.15cm} souvenir\hspace{0.15cm} paperweights}{number\hspace{0.15cm} of\hspace{0.15cm} paperweights\hspace{0.15cm} per\hspace{0.15cm} box}  = \dfrac{1657}{17} = 97.471

iv) Therefore we can say that 98 boxes will be needed to hold all the paperweights.

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Answer:

Lateral Area = 176 cm²

Step-by-step explanation:

The prism is a rectangular prism

Formula for Lateral Area of the rectangular prism = 2(l + b)*h

Where,

Length (l) = 4 cm

Breadth (b) = 4 cm

Height (h) = 11 cm

Plug in the values

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= 2(8)*11

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6 0
3 years ago
1st. (2 root 2 + root 3 ) ( 2 root 3 - root 2) 2nd.(root 5 + 2 root 10) (3 root 5 + root 10) 3rd.(4 root 6 - 3 root 3) (2 root 3
Viefleur [7K]

Answer:

1. 3√6 + 10

2. 35 + 7√50

3. 24√2 - 20√6 + 15√3 - 18

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Step-by-step explanation:

The questions are in surd form.

1. (2√2 + √3)(2√3 - √2)

open the parenthesis by multiplying both together .

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2. (√5 + 2√10)(3√5 + √10)

15 + √50 + 6√50 + 20

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3. (4√6 - 3√3)(2√3 - 5)

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8√9 × 2 - 20√6 - 18 + 15√3

24√2 - 20√6 + 15√3 - 18

4. (6√3 - 5√2)(2√2 - √3)

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5 (√10 - 3)(4 - 3√10)

4√10 - 30 - 12 + 9√10

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5 0
3 years ago
Rob had twenty-two dollars and two pennies to spend on six raffle tickets. How much did
Brilliant_brown [7]

Answer:

$3.07

Step-by-step explanation:

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hope this helps!

4 0
3 years ago
Read 2 more answers
Plssss help I will die:(
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Answer:

21

Step-by-step explanation:

Midpoint means the middle, so all you have to do is divide 42 by 2 :)

6 0
4 years ago
Use multiplication to describe the relationship between the dividend, the divisor and the quotient. Then use that relationship t
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In a division problem, ...

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Multiplying both sides of this equation by "divisor", we get ...

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3 years ago
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