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statuscvo [17]
3 years ago
5

How you do this ???????

Mathematics
2 answers:
Anon25 [30]3 years ago
8 0

Answer:

the answer is 5 because that is the difference which is what they are asking.

Step-by-step explanation:

12 -7 =5

. . . . . . .| . . . . .

-

. . . . . . .|

            | . . . . .

Diano4ka-milaya [45]3 years ago
4 0
Your looking for how many MORE so what you do is subtract the smaller number from the bigger one and that is how many more, so in this problem 5 more people are watching the otters.
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6z less than or equal to 18
yan [13]

Answer:

z<=3

Step-by-step explanation:

6z<=18

z<=18/6

z<=3

8 0
3 years ago
Am I correct on number 3
mrs_skeptik [129]
Yes your correct tttttttttttttttttttttttttttttttttttttttttttttttttttttttttt
                                                                               
4 0
4 years ago
Is 2.356... rational or irrational
777dan777 [17]

Answer:

Rational

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Calcium-41 is being used in studies testing the effectiveness of drugs for preventing osteoporosis. The half-life of calcium-41
Leviafan [203]

Answer:

332,193 years

Step-by-step explanation:

From the question above, we are to calculate the time in an half life question, hence, the formula is given as

t = In(Nt/No) ÷ -(In2/t½)

Where

t = time is takes for an substance to decay or reduce

Nt = Amount of sample after time = 2g

No = Initial amount of sample = 20g

t½ = Half life = 100,000 years

Hence,

t = In(2/20) ÷ (In 2/ 100,000)

t = 332192.80948874 years

Approximately = 332,193 years

7 0
3 years ago
In a box of 25 external hard disks, there are 2 defectives. An inspector examines 5 of these hard disks. Find the probability th
Salsk061 [2.6K]

Answer:

0.3667 or 36.67%

Step-by-step explanation:

The probability of getting at least 1 defective hard disk among the 5 (P(X>0)) is equal to 100% minus the probability of getting none defectives (1-P(X=0)).

If 23 out of 25 hard disks are non-defective, the probability is:

P(X>0) = 1 -P(X=0)\\P(X>0) = 1 -\frac{23}{25}*\frac{22}{24} *\frac{21}{23} *\frac{20}{22} *\frac{19}{21}\\ P(X>0) = 0.3667=36.67\%

The probability that there is at least 1 defective hard disk is 0.3667 or 36.67%.

8 0
3 years ago
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