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N76 [4]
3 years ago
14

Can anyone help me with any of these problems? You are supposed to find the surface area.

Mathematics
1 answer:
ale4655 [162]3 years ago
7 0
You first need to break each shape down. for example in the top right corner you have a pyramid and a triangular prism. find the area for those two shapes and add them together and you will have the surface area for the entire shape
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Help due soon will give brainliest
Bess [88]

Answer:

I believe the answer would be D) 12

Step-by-step explanation:

6 0
3 years ago
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Suppose that v is an eigenvector of matrix A with eigenvalue λA, and it is also an eigenvector of matrix B with eigenvalue λB. (
galben [10]

Answer:

(a) Yes, λ_{A}+λ_{B}

(b) Yes, λ_{A}λ_{B}

Step-by-step explanation:

First, lets understand what are eigenvectors and eigenvalues?

Note: I am using the notation λ_{A} to denote Lambda(A) sign.

v is an eigenvector of matrix A with eigenvalue λ_{A}

v is also eigenvector of matrix B with eigenvalue λ_{B}

So we can write this in equation form as

Av=λ_{A}v

So what does this equation say?

When you multiply any vector by A they do change their direction. any vector  that is in the same direction as of Av, then this v  is called the eigenvector of A. Av is λ_{A} times the original v. The number λ_{A} is the eigenvalue of A.

λ_{A} this number is very important and tells us what is happening when we multiply Av. Is it shrinking or expanding or reversed or something else?

It tells us everything we need to know!

Bonus:

By the way you can find out the eigenvalue of Av by using the following equation:

det(A-λI)=0

where I is identity matrix of the size of same as A.

Now lets come to the solution!

(a) Show that v is an eigenvector of A + B and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(A+B)(v)=Av+Bv=(λ_{A})v + (λ_{B})v=(λ_{A}+λ_{B})(v)

so,  (A+B)(v)=(λ_{A}+λ_{B})(v)

which means that v is also an eigenvector of A+B and the associated eigenvalues are λ_{A}+λ_{B}

(b) Show that v is an eigenvector of AB and find its associated eigenvalue.

The eigenvalues of A and B are λ_{A} and λ_{B}, then

(AB)(v)=A(Bv)=A(λ_{B})=λ_{B}(Av)=λ_{B}λ_{A}(v)=λ_{A}λ_{B}(v)

so,  

(AB)(v)=λ_{A}λ_{B}(v)

which means that v is also an eigenvector of AB and the associated eigenvalues are λ_{A}λ_{B}

5 0
3 years ago
What is the slope of the shown below?
Alexus [3.1K]

Answer:

<h2>B. 4</h2>

Step-by-step explanation:

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

We have the points (1, 1) and (3, 9). Substitute:

m=\dfrac{9-1}{3-1}=\dfrac{8}{2}=4

5 0
3 years ago
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(Look at screenshot)
PilotLPTM [1.2K]

#a

H(0)

It refers to y value on graph when x is 0

So here it refers to y intercept

  • y intercept (0,5)

Hence

  • H(0)=5

#b

Observe the graph

y intercept is not 0 so it's not true

#3

Domain is set of x values in graph

  • [0,oo)

#4

Range is set of y values on graph

  • [5,50]
4 0
2 years ago
lice walks along a road which can be modeled by the equation y=4x, where (0,0) represents her starting point. When she reaches a
olya-2409 [2.1K]

Answer:

(5,20)

Step-by-step explanation:

6 0
3 years ago
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