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dangina [55]
3 years ago
12

PLEASE HELP, WILL GIVE BRAINLIEST.

Mathematics
2 answers:
Arada [10]3 years ago
6 0
The answer to that question is 3
mel-nik [20]3 years ago
3 0
The answer is going to be C. 3


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Evaluate 2r (t – 1) ifr =<br> 4 and t<br> = 6
garri49 [273]

Answer:

40

Step-by-step explanation:

Step 1: Define

2r(t - 1)

r = 4

t = 6

Step 2: Substitute and Evaluate

2(4) · (6 - 1)

8 · 5

40

4 0
3 years ago
Read 2 more answers
How can Ari simplify the following expression? StartFraction 5 Over a minus 3 EndFraction minus 4 divided by 2 + StartFraction 1
Zielflug [23.3K]

Answer:

-\frac{8}{3}

Step-by-step explanation:

Given

\frac{5}{-3} - \frac{4}{2} + \frac{1}{-3}

Required

Simpify

The very first step is to take LCM of the given expression

\frac{-10 -4 - 2}{6}

Perform arithmetic operations o the numerator

-\frac{16}{6}

Divide the numerator and denominator by 2

-\frac{16/2}{6/2}

-\frac{8}{3}

The expression can't be further simplified;

Hence, \frac{5}{-3} - \frac{4}{2} + \frac{1}{-3} = -\frac{8}{3}

8 0
3 years ago
Shade in some or all of the grids to show that 2 ones is the same as 20 tenths
scZoUnD [109]
Given three grids with each grid representing one whole.
Each grid represents 1 ones and each vertical bar of a grid represent 1 tenth.
There are 10 vertical bars in each grid, hence each grid represent 1 ones = 10 tenths and 2 grids represent 2 ones = 20 tenths.

Therefore, two complete grids are to be shaded to <span>show that 2 ones is the same as 20 tenths</span>
4 0
3 years ago
A. Draw the image of ΔDEF after a rotation of 90° clockwise about the point (1,0). Label the image ΔD’E’F’.
irina [24]

Answer:

  see the attachment

Step-by-step explanation:

(a) Clockwise rotation moves a point from (x, y) to (y, -x).

__

(b) Reflection across x=1 moves a point from (x, y) to (2-x, y).

7 0
3 years ago
Part of a tiling design is shown. The center is a regular hexagon. A square is on each side of the hexagon, and an equilateral t
LiRa [457]
Area of the squares (6):
A 1 = 6 · 10² = 600 in²
Area of the equilateral triangles (6):
A 2 = 6 · 10²√3 / 4 = = 6 · 25 · 1.73 = 259.8 in²
Area of the hexagon:
A 3 = 6 · 10²√3/4 = 259.8 in²
Total area:
600 + 259.8 + 259.8 = 1,119.6 in²
Answer: C ) 
3 0
3 years ago
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