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PilotLPTM [1.2K]
3 years ago
6

What is y when y+2=3/4(x+4)

Mathematics
1 answer:
Yuki888 [10]3 years ago
4 0
Y=1+3x/4 would be the answer to solve for y
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Describe the steps you would take to sketch the graph p(x)=2x^(3)+7x^(2)-3x-18
mojhsa [17]

Answer:

When we have a given function, y = f(x), the general way of graphing the function is finding a lot of coordinate pairs (x, f(x)) and graphing them in a coordinate axis, and then connect them.

So here we have:

p(x) = 2x^(3)+7x^(2)-3x-18

Just let's find the value of p(x) for different values of x, and let's do it.

p(0) = 2*0^(3)+7*0^(2)-3*0-18 = -18

Then the point (0, -18) belongs to the graph

p(1) = 2*1^(3)+7*1^(2)-3*1-18 = 2 + 7 - 3 - 18 = -12

then the point (1, - 12) belongs to the graph.

p(-1) =  2*(-1)^(3)+7*(-1)^(2)-3*(-1)-18  = -2 + 7 + 3 - 18 = -10

then the point (-1, -10) belongs to the graph:

p(2) =  2*2^(3)+7*2^(2)-3*2-18 = 16 + 28 - 6 - 18 =  20

Then the point (2, 20) belongs to the graph

p(-2) =  2*(-2)^(3)+7*(-2)^(2)-3*(-2)-18 = -16 + 28 + 6 - 18 = 0

Then the point (-2, 0) belongs to the graph.

p(-3) =  2*(-3)^(3)+7*(-3)^(2)-3*(-3)-18 = -54 + 63 + 9 - 18 = 0

Then the point (-3, 0) belongs to the graph.

Now that we have 6 points we can graph them and try to connect them.

We also know that this is a cubic polynomial, so we can expect that it changes its direction two times (no more than that) then knowing that we can estimate a shape for the graph, and you will obtain something like the graph of the image below, where I just connected the known points.

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What is 1 1/5 X 3 3/4 ?
4vir4ik [10]

Answer:

4.5

Step-by-step explanation:

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It’s multiple choice , please help me !
ICE Princess25 [194]
Answer: a, c, e explanation: I did that test and got 100%
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3 years ago
emillo has 8,450 trees to plant in rows on his tree farm. He will plant 125 trees per row. How many full row of trees will he ha
Ymorist [56]
65 full row of Apple trees
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3 years ago
5000 for 5 years at 3.6% compounded monthly
Aleksandr [31]
Hello!

The sum at 5 years will be 8600.

Hope this helped! Need more help? Message me!
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