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creativ13 [48]
3 years ago
9

Create a set of coordinates to model a relation that is a linear function.

Mathematics
2 answers:
zvonat [6]3 years ago
8 0

Answer:

Y2 -y1/x2-x1

​

Y= (y2-y1/x2-x1)x + b

Y2= (y2-y1/x2-x1)x2 + b

B=y2 - (y2-y1/x2-x1)x2

Y= (y2-y1/x2-x1)x + [y2 - (y2-y1/x2-x1)

Step-by-step explanation:


hichkok12 [17]3 years ago
4 0
You just need any linear relationship and then just list out some points: For example y = 3x is a linear function. It means that every y value is triple the x. So some points would be (1,3) (2,6) (3,9) etc...
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What the volume of a hemisphere with a radius of 10 cm.
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4 years ago
What i do wrong<br> ?????
ruslelena [56]
Try to just put 10 or =10
7 0
3 years ago
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The legs of a right triangle are lengths x and x square root 3. The cosine of the smallest angle of the triangle is _____.
ICE Princess25 [194]
AC=x, BC=x√3, AB is a hypotenuse (look at the pic below)
x√3>x, consequently ∠B<∠A and we have to find cosB, which is (x√3)/AB.
<em>Let's find AB:</em>
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3 0
4 years ago
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What is the area of this composite figure?
soldi70 [24.7K]

Answer:

209 cm²

Step-by-step explanation:

This composite figure consist of two figures.

(1) Rectangle with length = 11 cm and width  = 16 cm.

(2) Triangle on the top of the rectangle with base = 11 cm and height = 6 cm.

Area of the rectangle = length × width

                                   = 11 × 16

                                   = 176 cm²

Area of the triangle = \frac{1}{2}(base) (height)

                                =  \frac{1}{2}(11) (6)

                                = 33 cm²

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8 0
4 years ago
Determine the area of a triangle with A=27.8 B = 107.3 c=4<br><br><br> Answer: B) 10 units^2
Mila [183]

Correct question:

Determine the area of a triangle with A=27.8° B = 107.3° c=4

Answer:

Area of the triangle is 5.04 units²

Step-by-step explanation:

Given;

A = 27.8°

B = 107.3°

C = 180 - (27.8 + 107.3) = 44.9°

c = 4

Now, we determine the remaining two sides of the triangle using sine rule

\frac{Sine \ A}{a} = \frac{Sine \ C}{c} \\\\a =  \frac{Sine A*\ c}{Sine C} = \frac{Sine(27.8) \ *4}{Sine(44.9) } =2.64\\\\\frac{Sine \ B}{b} = \frac{Sine \ C}{c}\\\\b=  \frac{Sine B*\ c}{Sine C} = \frac{Sine(107.3) \ *4}{Sine(44.9) } =5.41

Apply Hero's formula;

A = \sqrt{s(s-a)(s-b)(s-c)} \\\\s = \frac{a+b+c}{2} = \frac{2.64\ +\ 5.41\ +\ 4}{2} = 6.025\\\\A = \sqrt{6.025(6.025-2.64)(6.025-5.41)(6.025-4)} \\\\A = \sqrt{6.025(3.385)(0.615)(2.025)} \\\\A = \sqrt{25.3989} = 5.04 \ units^2

Therefore, area of the triangle is 5.04 units²

5 0
4 years ago
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