B. Ben
Because “25” can be changed to a five
You can set each equation to 0 so it would look like this:
And solve
4n+5=0. 3n-7=0
-5=-5. +7=+7
4n = 5. 3n = 7
4n/4 = 5/4. 3n/3 = 7/3
n = 5/4 n = 7/3
The first set of answers are the correct answers for n.
Answer:
(2-6)(10) plus 3 to the power of 2, is <u>-31</u>.
Explanation:
Three to the power of two plus parenthesis two minus six parenthesis parenthesis ten. This is the same as the sum or addition of 3 times 3(3 times itself two times), and 2 minus 6 times 10.
This expression can be represented by (3^2) + (2-6)(10) which is (3 × 3) + (-4 × 10) which is 9 + -40 which simplifies to -31
Answer:
138 degrees
Step-by-step explanation:
I'm assuming you meant measurement of angle 1 = 42 degrees.
If d//m, then angles 1,4,5, and 8 all have to have the same angle measurement. Likewise, angles 2,3,6, and 7 all have to have the same angle measurement.
So, because we know the angle measurement of angle 1, we can use that to calculate angle 2. Because angle 1 + angle 2 = 180 degrees, we can just do 180 - angle 1 to calculate the measurement of angle 2, which would be 138 degrees. Because angle 2 and angle 7 have to be the same measurement in order to have d//m, angle 7 must be 138 degrees.
Answer:
There is not enough evidence to support the claim that the true average penetration is at most 50 mils.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 50
Sample mean, = 52.8
Sample size, n = 45
Alpha, α = 0.05
Sample standard deviation, s = 4.5
First, we design the null and the alternate hypothesis
We use one-tailed t test to perform this hypothesis.
Formula:
Putting all the values, we have
Now,
Since,
The calculated test statistic is greater than the critical value, we fail to accept the null hypothesis and reject it. We accept the alternate hypothesis.
Conclusion:
There is not enough evidence to support the claim that the true average penetration is at most 50 mils.