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2 years ago

What is the value of x?

Mathematics

1 answer:

Gala2k [10]2 years ago

8 0

Answer:I'm guessing 48

Step-by-step explanation:

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I need help with #2 (click the attached photo to view properly)<br>I will mark Branliest

Shtirlitz [24]

Hi there! :)

$\large\boxed{j(h(x))(2) = 31}$

Solve for j(h(x)):

h(x) = x² + 4

j(x) = 4x - 1

Substitute in h(x) into "x":

j(h(x)) = 4(x² + 4) - 1

j(h(x)) = 4x² + 16 - 1

j(h(x)) = 4x² + 15

Solve at x = 2:

4(2)² + 15 = 4(4) + 15 = 31.

7 0

3 years ago

Solve for x<br> (1/x) -2/3 = (4x)

Vadim26 [7]

The value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

Step-by-step explanation:

The equation is $\frac{1}{x}-\frac{2}{3}=4 x$

Subtracting by $4x$ on both sides,

$\frac{1}{x}-\frac{2}{3}-4 x=0$

Taking LCM,

$\frac{3-12 x^{2}-2 x}{3 x}=0$

Multiplying by 3x on both sides,

$-12 x^{2}-2 x+3=0$

Dividing by (-) on both sides,

$12 x^{2}+2 x-3=0$

Using quadratic formula, we can solve for x.

$\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}$

Taking out common term 2, we get,

$\begin{array}{l}{x=\frac{-2(1 \pm \sqrt{37})}{24}} \\{x=\frac{-1 \pm \sqrt{37}}{12}}\end{array}$

Thus, the value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

4 0

3 years ago

Order each set of numbers from least to greatest.<br><br><br> PLZ HELP ASAP

Wittaler [7]

Answer:

$\frac{41}{3} < 14 < \sqrt{200}$

<u> $0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} }$ </u>

Step-by-step explanation:

$\sqrt{200} = 10 \sqrt{2} = 14.1 \\ 14 = 14 \\ \frac{41}{3} = 13.6$

So ;

$\frac{41}{3} < 14 < \sqrt{200} \\ 13.6 < 14 < 14.1$

$\frac{2}{3} = 0.66 \\ \sqrt{ \frac{9}{16} } = \frac{3}{4} = 0.75 \\ 0.6 = 0.6$

So ;

$0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } \\ 0.6 < 0.66 < 0.75$

I hope I helped you^_^

6 0

2 years ago

Michael rotates ABC to form the image A'B'C'. The table shows the corresponding vertices for ABC and AA'B'C'. What degree of rot

babunello [35]

Answer:

90 degree rotation in the clockwise direction.

Step-by-step explanation:

Point A transforms to A'

- that is x coordinate: 2 ---> 3

and y coordinate 3 ---> -2

So the rotation is clockwise from Quadrant1 to Quadrant 4.

The slope of OA = 3/2 and the slope of OA' = -2/3.

The product of these slopes = 3/2 * -2/3 = -1 so the lines are perpendicular - that is the line has passed through an angle of 90 degrees.

A similar result occurs if we consider points B, C and D.

3 0

3 years ago

Let the measure of Arc B C D = a°. Because Arc B C D and Arc B A D form a circle, and a circle measures 360°, the measure of Arc

zepelin [54]

Answer:

Step-by-step explanation:

inscribed angle

5 0

2 years ago

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