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kirza4 [7]
4 years ago
7

Show that f(x)=πx-2 and f-1(x)=(x+2/π) are inverse functions of one another

Mathematics
1 answer:
iVinArrow [24]4 years ago
5 0
They are not inverse functions of one another. For f(x) and g(x) to be inverses of each other, f(g(x)) = x. In this case, pi(x+2/pi)-2 = pi* x, which is not x.
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Answer:

The probability that exactly 12 buyers would prefer green

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Step-by-step explanation:

We are given that

p=50%=50/100=0.50

n=14

We have to find the probability that exactly 12 buyers would prefer green.

q=1-p

q=1-0.50=0.50

Using binomial distribution formula

P(X=x)=nC_r p^r q^{n-r}

P(x=12)=14C_{12}(0.50)^{12}(0.50)^{14-12}

P(x=12)=14C_{12}(0.50)^{12}(0.50)^2

P(x=12)=14C_{12}(0.50)^{14}

P(x=12)=\frac{14!}{12!2!}(0.50)^{14}

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P(x=12)=91\cdot (0.50)^{14}

P(x=12)=0.00555

Hence, the probability that exactly 12 buyers would prefer green

=0.00555

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3 years ago
What is the sum of 2/10 and 9/100
zhannawk [14.2K]
First we need to find a common denominator

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Answer:

8.81% probability that the student answers exactly 4 questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either he answers it correctly, or he does not. The probability of answering a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A multiple choice exam has ten questions.

This means that n = 10

The probability of answering any question correctly is 0.20.

This means that p = 0.2

What is the probability that the student answers exactly 4 questions correctly

This is P(X = 4).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 4) = C_{10,4}.(0.2)^{4}.(0.8)^{6} = 0.0881

8.81% probability that the student answers exactly 4 questions correctly

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