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2 years ago

8

Help me please!!i need the answer now:(

1 answer:

Andrews [41]2 years ago

6 0

Answer:

Step-by-step

Let us assume that the third leg is X. So, X^2 + 2^2 = 5^2.X^2 = 25 - 4.X^2 = 21.X = root 21.

a right triangle, hypotenuse=5 cm, one leg=2 cm, the other leg=xApplying the Pythagorean theorem:5^2=2^2+x^2, 25=4+x^2,x^2=25–4=21, x=sqrt(21), x=4,58 cmThe measurement of the other leg is 4,58 cm

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0.097 = 97 / 1000

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PLEASE HELP ASAP ILL GIVE BRAINLIEST!!!!!<br><br>find measure of arc MK

Gwar [14]

Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

$\sf \cos(\theta)=\dfrac{A}{H}$

where:

$\theta$ is the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Given:

$\theta$ = ∠KLM
A = LN = 8
H = KL = 15.2

$\implies \sf \cos(KLM)=\dfrac{8}{15.2}$

$\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)$

$\implies \sf \angle KLM=58.24313614^{\circ}$

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}$

Given:

r = 15.2
∠KLM = 58.24313614°

$\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)$

$\implies \textsf{Arc length MK}=\sf 15.45132428\:units$

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1 year ago

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iogann1982 [59]

C. 728

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1 year ago