Need help asap im not good at math
1 answer:
g(x):
flip f(x) over x-axist and next translate 2 units down.
Look at the picture.
<h3>Therefore your answer is: B. g(x) = -x² - 2</h3>Translations
y = f (x) + m up m units
y = f (x) - m down m units
y = f (x + m) left m units
y = f (x - m) right m units
Stretches/Shrinks
y = n · f (x) stretch vertically by a factor of n
y = 1/n · f (x) shrink vertically by a factor of m (stretch by 1/n)
y = f (1/n x) stretch horizonally by a factor of n
y = f (nx) shrink horizontally by a factor of n (stretch by 1/n)
Reflections
y = - f (x) reflect over x-axis (over line y = 0)
y = f (- x) reflect over y-axis (over line x = 0)
x = f (y) reflect over line y = x
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Answer:
(9) $339076.60 (10) $72000 (11) $220800
Note: Kindly find an attached copy of the complete question given below. i solved for 9,10,11 only.
Step-by-step explanation:
Solution
Given that:
Betty set aside $200/month
With a 401 (k) savings
t = 40 years
APR = 5.4%
Now we find the balance in her account after 40 years.
Now,
A = PMT [(1 +r/n)^nt -1]/(r/n)
A = 200 [ (1 + 0.054/12)^(12)(40) - 1]/(0.054/12)
A= $339076.60
(10) Recall that:
t = 40 years
Per month deposit = $150 dollar
The total deposit becomes
t = 40 * 12 = 480 Month
Total deposit = 480 * 150
=$72000
(11) Now we find the less money she received in her paychecks
Thus
Without monthly saving paycheck is =$2300
Now,
For 40 years becomes = $2300 * 40 * 12
=$1,104000
So,
20% of tax deducted = 20/100 * $1,104000
=$220800
Therefore the less amount received in 40 years is $220800
Note:( My research for the complete question was from quiz let, chegg)
Answer:
- local minimum at x = -3-2√14
- local maximum at x = -3+2√14
Step-by-step explanation:
The first derivative simplifies to ...
d/dx( ) = -(x^2 +6x -47)/(x^2 -9x +20)^2
This has zeros that can be found by the usual methods of solving quadratics:
x = -3 ±2√14
The positive value of x corresponds to what I might call an "apex." (See the first attachment.) The negative value is where the function turns around an approaches the horizontal asymptote from below. (See the second attachment.)
