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3 years ago

I need help with this problem please if you can help I would really appreciate it and the problem is number 10

Mathematics

1 answer:

aev [14]3 years ago

4 0

Answer:

g(-5) = -127

Step-by-step explanation:

Plug in -5 for x:

g(-5) = (-5)^3 - 2

= -125 - 2

= -127

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WILL GIVE A BRAINLIEST IF UR RIGHT PLEASE HELP!!!

stellarik [79]

For (8, 16): 3(8) - 8 = 24 - 8 = 16 [solution]
For (3, 4): 3(3) - 8 = 9 - 8 = 1 [not a solution]
For (-6, -26): 3(-6) - 8 = -18 - 8 = -26 [solution]
For (-10, -38): 3(-10) - 8 = -30 - 8 = -38 [solution]

I hope I helped! :)

6 0

4 years ago

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Use the X intercept method to find all real solutions of the equation x^3-10x^2+17x+28=0

irakobra [83]

Answer:

They are -1, 4 and 7.

Step-by-step explanation:

x^3 - 10x^2 + 17x + 28 = 0

Observation of this equation shows that there is an x -intercept at x = -1 because

-1^3 - 10^(-1)^2 - 17(1) + 28 = -28 + 28

= 0.

So x + 1 must be a factor so we can do the division:

x + 1 ) x^3 - 10x^2 + 17x + 28 ( x^2 - 11x + 28

x^3 + x^2

-11x^2 + 17x

-11x^2 - 11x

28x^2 + 28

x^2 - 11x + 28 = ( x - 4)(x - 7)

x = 4, 7.

6 0

4 years ago

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Which is equivalent to 3v8

Tomtit [17]

Answer:

Step-by-step explanation:

= $\sqrt[3]{8}^{x}\\$

= Since $\sqrt[3]{} = ^{1/3}$

= So, It becomes :

= $8^{\frac{x}{3}$

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4 years ago

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Find a equation with a cube x3 =1000

Dima020 [189]

I hope this helps you

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3 years ago

Please help ASAP !!!

enot [183]

Answer: x=3

Step-by-step explanation:

To solve this problem you must apply the proccedure shown below:

- Multiply both sides of the equation by 3:

$3(2x-3)=3(\frac{x^2}{3})\\6x-9=x^{2}$

- Now you must make the equation equal to zero as following:

$6x-9=x^{2}\\x^{2}-6x+9=0$

- Factor it, as you can see below. Therefore, you obtain the following result:

$(x-3)(x-3)=0\\(x-3)^2=0\\x=3$

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3 years ago

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