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DaniilM [7]
3 years ago
5

117,456 rounded to nearest tenth

Mathematics
2 answers:
hram777 [196]3 years ago
5 0
117,500 will be your answer
tatuchka [14]3 years ago
4 0
117,460 is the answer
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1-cos^2 A / sec^2 A - tan^2 A
tiny-mole [99]
I hope this helps you



✔cos^2A+sin^2A=1


✔1-cos^2A=sin^2A

✔cos2A=cos^2A-sin^2A

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secA=1/cosA


tgA=sinA/cosA


sin^2A/1/cos^2A-sin^2A/cos^2A


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6 0
3 years ago
Show work. This is a BC calculus problem.
stepan [7]

Answer:

D.

Step-by-step explanation:

Remember that the limit definition of a derivative at a point is:

\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}

Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:

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Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).

The answer will thus be D.

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Step-by-step explanation:

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