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LenKa [72]
3 years ago
11

For lines c, d and e, m_1= 90° and m_3=90° For the given diagram and angle measures, use complete sentences to describe each pai

r of lines as parallel or perpendicular. In your description, include the special angle relationship between angles 1 and 3. a. lines d and e b. lines d and c​

Mathematics
1 answer:
alexandr402 [8]3 years ago
7 0

Answer:

i don't know how to figure out this

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Solve the system of equations<br> 3x + y = 3<br> x + y = 2
Pachacha [2.7K]

Answer:

(1/2, 3/2)

Step-by-step explanation:

solve the 1st variable in one of the equations and then substitute it and the result will be turned into the other equation.

4 0
3 years ago
The temperatures at 6:00 am one morning in four cities are given below.
Andre45 [30]

Answer:

-9

Step-by-step explanation:

8 0
3 years ago
True or False? A circumscribed about the quadrilateral below .
Elis [28]

Answer:

TRUE

Step-by-step explanation:

The center is visible

4 0
3 years ago
Read 2 more answers
Given sin(u)= -7/25 and cos(v) = -4/5, what is the exact value of cos(u-v) if both angles are in quadrant 3
solmaris [256]

Given:

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

To find:

The exact value of cos(u-v) if both angles are in quadrant 3.

Solution:

In 3rd quadrant, cos and sin both trigonometric ratios are negative.

We have,

\sin (u)=-\dfrac{7}{25}

\cos (v)=-\dfrac{4}{5}

Now,

\cos (u)=-\sqrt{1-\sin^2 (u)}

\cos (u)=-\sqrt{1-(-\dfrac{7}{25})^2}

\cos (u)=-\sqrt{1-\dfrac{49}{625}}

\cos (u)=-\sqrt{\dfrac{625-49}{625}}

On further simplification, we get

\cos (u)=-\sqrt{\dfrac{576}{625}}

\cos (u)=-\dfrac{24}{25}

Similarly,

\sin (v)=-\sqrt{1-\cos^2 (v)}

\sin (v)=-\sqrt{1-(-\dfrac{4}{5})^2}

\sin (v)=-\sqrt{1-\dfrac{16}{25}}

\sin (v)=-\sqrt{\dfrac{25-16}{25}}

\sin (v)=-\sqrt{\dfrac{9}{25}}

\sin (v)=-\dfrac{3}{5}

Now,

\cos (u-v)=\cos u\cos v+\sin u\sin v

\cos (u-v)=\left(-\dfrac{24}{25}\right)\left(-\dfrac{4}{5}\right)+\left(-\dfrac{7}{25}\right)\left(-\dfrac{3}{25}\right)

\cos (u-v)=\dfrac{96}{625}+\dfrac{21}{625}

\cos (u-v)=\dfrac{1 17}{625}

Therefore, the value of cos (u-v) is 0.1872.

6 0
3 years ago
What is the volume of a cone with a diameter of 30 feet and a height of 60 feet? Use 3.14 for π.
AysviL [449]

Answer:

14130 ft^3

Step-by-step explanation:

The formula for the volume of a cone of radius r and height h is

V = (1/3)*pi*r^2*h.

Here, V = (1/3)(3.14)(15 ft)^2*(60 ft) = 20*3.14*225 ft^3 = 14130 ft^3


3 0
3 years ago
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