To find the answer, set up a system of equations.
Let x=adult tickets and y=senior citizen tickets.
x+y=556
22x+12y=8492
Change the first equation to make it easy to combine with the second equation.
y=556-x
Now substitute (556-x) for y in the second equation.
22x+12(556-x)=8492
Simplify and combine like terms.
22x+6672-12x=8492
10x=1820
x=182
182 adult tickets were sold, so to solve for the number of senior citizen tickets sold, subtract 182 from 556.
556-182=374
374 senior citizen tickets were sold.
From the 64 values in the table on the left, count how many fall within the given ranges under the "classes" column in the table on the right. The "frequency" is the number of values in the data that belong to a given "class".
For example, "< -16.0" means "values below -16.0". Only one number satisfies this: -16.2 (first row, third column). So the frequency for this class is just 1.
Then for the range "-15.9 - 13.0", which probably means "numbers between 15.9 and -13.0, inclusive", the frequency is 0 because every number in the table is larger than the ones in this range.
And so on.
Answer:
N= -44/9 Hope this helped, <3
Step-by-step explanation:
Let's solve your equation step-by-step.
n−2=10n+42
Step 1: Subtract 10n from both sides.
n−2−10n=10n+42−10n
−9n−2=42
Step 2: Add 2 to both sides.
−9n−2+2=42+2
−9n=44
Step 3: Divide both sides by -9.
Answer:
it the first choice you ate three chocolate independently
