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Mazyrski [523]
3 years ago
9

Between which pair of consecutive integers does √111 lie

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
7 0
B. 10 and 11
This is because 10x10 is 100, so thats less than what you need and then 11x11 is 121, and that is more than you need... So it would be between 10 and 11.
natulia [17]3 years ago
5 0

Answer:

The given lie between 10 and 11

B is correct

Step-by-step explanation:

We need to find pair of number in which \sqrt{111} lie between them.

Let given number lie between two integer x and y

Thus,

x

Taking square both sides

x^2

As we assumed x and y are integers.

We will choose two number across 111 those are perfect square.

100

10^2

Taking square root all sides

10

Hence, The given lie between 10 and 11.

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A number cube with the numbers 1 through 6 is rolled. What is the probability of the number cube showing a 4 or a number less th
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Answer:

Step-by-step explanation:

The probability is

P

(

A

)

=

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3

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|

Ω

|

and the number of results that fulfill the given condition

|

A

|

.

In this case

Ω

=

{

1

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2

,

3

,

4

,

5

,

6

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|

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{

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|

A

|

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2

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Finally to calculate the probability we have to divide

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A

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by

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Ω

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.

P

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A

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=

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A

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Ω

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=

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