Between which pair of consecutive integers does √111 lie

2 answers:

lisabon 2012 [21]3 years ago

7 0

B. 10 and 11
This is because 10x10 is 100, so thats less than what you need and then 11x11 is 121, and that is more than you need... So it would be between 10 and 11.

natulia [17]3 years ago

5 0

Answer:

The given lie between 10 and 11

B is correct

Step-by-step explanation:

We need to find pair of number in which $\sqrt{111}$ lie between them.

Let given number lie between two integer x and y

Thus,

$x$

Taking square both sides

$x^2$

As we assumed x and y are integers.

We will choose two number across 111 those are perfect square.

$100$

$10^2$

Taking square root all sides

$10$

Hence, The given lie between 10 and 11.

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Which box plot correctly displays the data set with a maximum of 48, a minimum of 27, a median of 36, an upper quartile of 45, a

Vitek1552 [10]

Answer:

Image 1

Step-by-step explanation:

To answer this question, we need to know how to use a box plot.

I've attached an image that demonstrates this well and can teach you what each part of the box plot means.

Specifically, the 2 farthest dots at the end are the minimum and maximum. The two sides where the box starts are the lower and upper quartiles. Finally, the line in the middle of the box is the median.

With this, we can analyze each box plot and determine which one is correct.

Box Plot 1: Everything is plotted correctly- Maximum and minimum plotted correctly, median plotted correctly, upper and lower quartile plotted correctly.

Box Plot 2: Everything plotted correctly EXCEPT maximum of 48 is represented at 46.

Box Plot 3: Everything plotted correctly EXCEPT the upper quartile of 45 is at 39.

Box Plot 4: Upper quartile represented at 39 and maximum represented at 46 are both incorrect.