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Mazyrski [523]
3 years ago
9

Between which pair of consecutive integers does √111 lie

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
7 0
B. 10 and 11
This is because 10x10 is 100, so thats less than what you need and then 11x11 is 121, and that is more than you need... So it would be between 10 and 11.
natulia [17]3 years ago
5 0

Answer:

The given lie between 10 and 11

B is correct

Step-by-step explanation:

We need to find pair of number in which \sqrt{111} lie between them.

Let given number lie between two integer x and y

Thus,

x

Taking square both sides

x^2

As we assumed x and y are integers.

We will choose two number across 111 those are perfect square.

100

10^2

Taking square root all sides

10

Hence, The given lie between 10 and 11.

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The depreciating value of a semi-truck can be modeled by y = Ao(0.84)x, where y is the remaining value of the semi, x is the tim
NemiM [27]
The value of the truck initially, Ao is
83000

1-0.16=0.84
1-0.26=0.74

After one year the value
Y=83,000×(0.84)=69,720
Y=83,000×(0.74)=61,420
When you compare the results you will see that the graph would fall at a faster rate to the right because the depreciation rate of 26% is higher than the depreciation rate of 16%

Hope it helps
8 0
3 years ago
The mean of a particular set of 7 numbers is 4. Six of the numbers in the set are known: 1,2,2,5,7,and 8.
Setler [38]
\dfrac{1+2+2+5+7+8+x}{7}=4\\
\dfrac{25+x}{7}=4\\
25+x=28\\
\boxed{x=3}

8 0
3 years ago
A line of best fit predicts that when x equals 28 y will equal 27.255 but y actually equals 26 what is the residual in this case
Kobotan [32]

Answer:

The answer is -1.255 for residual value.

Step-by-step explanation:

We are tasked to solve for the residual value given that when x equals 29, y will be equals to 27.255. But, when it is tested, y actual value is 26. The formula in solving residual is shown below:

Residual value = Observed value - predicted value

Residual value =  26 - 27.255

Residual values = -1.255

4 0
3 years ago
If anyone could help?
Trava [24]

Answer:

y=\frac{5}{7}x and y=\frac{7}{9}x

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In y=\frac{5}{7}x when x=3, y=15/4≈2.14

In y=\frac{3}{5}x when x=3, y=1.8

In y=\frac{7}{9}x when x=3, y≈2.33

In y=\frac{7}{11}x when x=3, y≈1.90

We can observe that in two cases, y=\frac{5}{7}x and y=\frac{7}{9}x, y is greater than 2.


5 0
2 years ago
PLZZZZZ I AM TIMED AND IT IS ON 10 MINUTES
shutvik [7]

Answer:

Teaching students and collaborating with teachers on instructional content

Step-by-step explanation:(Hope This Helps)

6 0
3 years ago
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