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Mazyrski [523]
3 years ago
9

Between which pair of consecutive integers does √111 lie

Mathematics
2 answers:
lisabon 2012 [21]3 years ago
7 0
B. 10 and 11
This is because 10x10 is 100, so thats less than what you need and then 11x11 is 121, and that is more than you need... So it would be between 10 and 11.
natulia [17]3 years ago
5 0

Answer:

The given lie between 10 and 11

B is correct

Step-by-step explanation:

We need to find pair of number in which \sqrt{111} lie between them.

Let given number lie between two integer x and y

Thus,

x

Taking square both sides

x^2

As we assumed x and y are integers.

We will choose two number across 111 those are perfect square.

100

10^2

Taking square root all sides

10

Hence, The given lie between 10 and 11.

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The standard deviation of a point estimator is the _____. a. standard error b. sample statistic c. point estimate d. sampling er
ivann1987 [24]

The standard deviation of a point estimator is the <u>standard error.</u>

"The point estimate is used to estimate the exact value of any parameter. For example, an internet poll says that 45% of Americans are concerned for the environment."

"Point estimates is a good measure but the problem with this parameter is that the sample of the statistics may vary so that there is a chance of sampling error."

"As the researcher is unable to presume that closeness of the sample statistics parameter with respect to the parameter so researcher refers to calculate the standard error instead of point estimate."

To learn more about standard error here

brainly.com/question/13179711

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4 0
1 year ago
The total of a regular polygon's interior angles is 3420°.
DanielleElmas [232]

Step-by-step explanation:

(n-2)×180=3420

180n-360=3420

180n=3420+360

180n=3780

n=3780/180

n=21

that is, the number of sides is 21

to get the size of each exterior angle=

360/21

=17.14°

4 0
2 years ago
The distance between City A and City B is 250 miles. A length of 2.1 feet represents this distance on a certain wall map. City C
tigry1 [53]

Answer:

650 miles

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

5 0
3 years ago
Read 2 more answers
Solve for x round to the nearest tenth of a degree,if necessary.​
Ostrovityanka [42]

Answer:

Solution given:

Cos X=Adjacent/hypotenuse

Cos X=6.5/8.4

x=Cos-¹(6.5/8.4)

<u>x=39.3</u>°

4 0
2 years ago
If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000
zavuch27 [327]

Answer:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

X \sim N(100000,20000)  

Where \mu=100000 and \sigma=20000

We are interested on this probability

P(X>117000)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)

And we can find this probability using the complement rule and the normal standard table or excel:

P(z>0.85)=1-P(z

The firgure attached illustrate the problem

7 0
2 years ago
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