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Nady [450]
3 years ago
14

Annabelle has the following containers of paint left over. 1/2 gallon 3/4 quart and one fourth gallon. Annabelle put the leftove

r paint in pint container.How many pints container did Annabelle fill. explain
Mathematics
1 answer:
Studentka2010 [4]3 years ago
6 0
11.5 pints in a half gallon there is 8 pints and in a 3/4 quart has 1.5 an a one fourth gallon has 2 pints
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10 POINTS! I NEED THIS QUESTION PLS! FIND THE AREA!!! THERE IS A SQUARE LEFT SIDE OF THE SQUARE IS 12 INCHES, WHATS THE AREA?
zubka84 [21]

Answer:

144

Step-by-step explanation:

12x12=144

4 0
2 years ago
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HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP HELP I NEED HELP ASAP
ivolga24 [154]

<u>Answer:</u>

<h2>A = 15 u²</h2>

<u>Explanation:</u>

according to the coordinates the triangles is right at the pair (2, -3)

the area of the triangle = height × base × 1/2

the <u>height</u> is the line passing through the pairs (-1, 6) and (2, -3)

h² = (2-(-1))²+(-3-6)²

h² = 3² + (-9)²

h² = 9 + 81

h² = 90

h = √90

the <u>base</u> is the line passing through the pairs (5, -2) and (2, -3)

b² = (2-5)²+(-3-(-2))²

b² = 3² + (-3+2)²

b² = 9 + 1

b² = 10

b = √10

A = h×b×1/2

A = √90×√10×1/2

A = √900×1/2

A = 30×1/2

A = 15 u²

5 0
3 years ago
Match the following items by evaluating the expression for x = -6.
Kryger [21]

Step-by-step explanation:

Put the value of x = -6 to all expressions:

x^{-2}=(-6)^{-2}=\dfrac{1}{(-6)^2}=\dfrac{1}{6}\qquad\text{used}\ a^{-n}=\dfrac{1}{a^n}\\=====================\\x^{-1}=(-6)^{-1}=\dfrac{1}{(-6)^1}=-\dfrac{1}{6}\\=====================\\x^0=(-6)^0=1\qquad a^0=1\ \text{for all real numbers except 0}\\=====================\\x^1=(-6)^1=-6\qquad a^1=a\ \text{for all real numbers}\\=====================\\x^2=(-6)^2=36

5 0
3 years ago
Can any one help ? Please can some one help m please help me
miskamm [114]

hope this helps

I really tried my best to give you a very direct answer

4 0
3 years ago
Can you help? Thanks!​
Kitty [74]

Answer:

(7, 2).

Step-by-step explanation:

The median from A intersects BC at it's midpoint.

To find the midpoint of BC:

This is (x1, y1) where x1 = (sum of the x_values of B and C) / 2)  and where y1

= (sum of the y_values of B and C) / 2)

This is (2+12)/2,  (1 + 3)/2

= (7, 2).

4 0
2 years ago
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