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3 years ago

Simplify (3x − 5) − (4x + 6).

Mathematics

1 answer:

irinina [24]3 years ago

3 0

(3x − 5) − (4x + 6)

Pretend that there is a 1 in front of the first bracket.

Pretend that there is a -1 in front of the second bracket.

Multiply the first bracket by 1

(1)(3x)=3x, (1)(-5)=-5

Multiply the second bracket by -1

(-1)(4)=-4, (-1)(6)=-6

3x-5-4x-6

3x-4x-5-6 ( combine like terms)

-x-11

Answer: -x-11 or -11-x

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What is 20 times 18 1/3

hodyreva [135]

The answer is 120.............

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3 years ago

Please help me with this question I’m so confused

zavuch27 [327]

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4 0

1 year ago

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Evaluate the series 4 – 2 + 1 – 0.5 + 0.25 to S10. Round to the nearest hundredth.

aleksklad [387]

The initial term of this geometric series is 4, and the common ratio is -1/2. The sum is given by

$S_{n}=a_{1}\dfrac{r^{n}-1}{r-1}\\\\S_{10}=4\cdot \dfrac{(-\frac{1}{2})^{10}-1}{-\frac{1}{2}-1}=4\cdot \dfrac{(\frac{1}{1024}-1)}{(-\frac{3}{2})}\\\\=\dfrac{8}{3}\cdot \dfrac{1023}{1024}=\dfrac{341}{128}$

The sum is approximately 2.66.

4 0

3 years ago

Find the second partial derivatives of the following functions

artcher [175]

(a) z = 3x ² - 4xy + 15y ²

has first-order partial derivatives

∂z/∂x = 6x - 4y

∂z/∂y = -4x + 30y

and thus second-order partial derivatives

∂²z/∂x ² = 6

∂²z/∂x∂y = -4

∂²z/∂y∂x = -4

∂²z/∂y ² = 30

where ∂²z/∂x∂y = ∂/∂x [∂z/∂y] and ∂²z/∂y∂x = ∂/∂y [∂z/∂x].

(b) z = 4x eʸ

∂z/∂x = 4eʸ

∂z/∂y = 4x eʸ

∂²z/∂x ² = 0

∂²z/∂x∂y = 4eʸ

∂²z/∂y∂x = 4eʸ

∂²z/∂y ² = 4x eʸ

∂z/∂x = 6 ln(y)

∂z/∂y = 6x/y

∂²z/∂x ² = 0

∂²z/∂x∂y = 6/y

∂²z/∂y∂x = 6/y

∂²z/∂y ² = -6x/y ²

6 0

2 years ago

HELP PLEASE!

Bas_tet [7]

Answer:

27/8

Step-by-step explanation:

3 3/8

you multiply the denominator by the whole number and then add into numerator. so

8 x 3 = 24

24+ 3 =27

Answer= 27/8

6 0

3 years ago

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