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musickatia [10]
3 years ago
5

Can anyone explain how to find the answer? for H

Mathematics
1 answer:
lesya692 [45]3 years ago
6 0
\sqrt[3]{ \frac{27}{125} } =   \sqrt[3]{27} / \sqrt[3]{125}  \\     \sqrt[3]{27} / \sqrt[3]{125}  = 3/5

Final answer: 3/5
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The time for a professor to grade an exam is normally distributed with a mean of 16.3 minutes and a standard deviation of 4.2 mi
dem82 [27]

Answer:

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 16.3, \sigma = 4.2

What is the probability that a randomly selected exam will require more than 15 minutes to grade

This is 1 subtracted by the pvalue of Z when X = 15. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{15 - 16.3}{4.2}

Z = -0.31

Z = -0.31 has a pvalue of 0.3783.

1 - 0.3783 = 0.6217

62.17% probability that a randomly selected exam will require more than 15 minutes to grade

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3 years ago
Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch radius A = sq. in.
katovenus [111]
\bf \textit{area of an equilateral triangle}\\\\
A=\cfrac{s^2\sqrt{3}}{4}\qquad 
\begin{cases}
s=length~of\\
\qquad a~side\\
-------\\
s=6
\end{cases}\implies A=\cfrac{6^2\sqrt{3}}{4}\implies A=\cfrac{36\sqrt{3}}{4}
\\\\\\
A=9\sqrt{3}
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