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Ostrovityanka [42]
3 years ago
13

Find the value of x.

Mathematics
1 answer:
masha68 [24]3 years ago
6 0

Answer:

Step-by-step explanation:

-39+x+146=180

x+107=180

x=180-107=73

x=73°

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|3x|=9, solve absolute value equation
Mashutka [201]
|3x|=9

3x=9 -3x=9
X=9/3 x=9/-3
x=3 x=-3

Whenever you have an absolute value sign you have to find both the positive and the negative because they didnt signs into the equation but sometimes a question will ask for strictly the positive value or the negative value but if its not stated, find both.
4 0
3 years ago
If Lin runs 21 laps at the same rate (1.2 minutes per lap) how long does it take her?
Firlakuza [10]

Answer:

It takes her 25.2 mintes

Step-by-step explanation:

You can just multiply 21 by 1.2 because that's how long she takes per lap and you can get 25.2

8 0
3 years ago
Read 2 more answers
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
I need help with all 8!
a_sh-v [17]
1) D
2)
3) B
4 ) F
5)C
6) F
7) D
8) C

I'm not sure about questions 4 and 7, but they may be correct.

I couldn't because I couldn't see the 2nd question
3 0
3 years ago
Multiply and simplify. (x + 3)(x - 8)
Kazeer [188]

Answer:

x^{2} - 5x - 24

Step-by-step explanation:

( x + 3 )( x - 8 ) =

x^{2} - 8x + 3x - 24 = x^{2} - 5x -24

4 0
3 years ago
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