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ratelena [41]
3 years ago
14

How do you solve (2x+y)^5 using Pascal’s Triangle?

Mathematics
1 answer:
pshichka [43]3 years ago
4 0
Check the picture below.

then recall that the first term start with a highest exponent and gradually wanes, and the second term starts at 0, and gradually goes up.  Then using  those coefficients, expand away.


\bf ( 2x+y )^5
\\\\\\
1( 2x )^5(y)^0~+~5( 2x )^4( y )^1~+~10( 2x )^3( y )^2~+~10( 2x )^2( y )^3\\\\+~5( 2x )^1( y )^4~+~1( 2x )^0( y )^5
\\\\\\
2^5x^5+5(2^4x^4)(y)+10(2^3x^3)(y^2)+10(2^2x^2)(y^3)\\\\
+5(2^1x^1)(y^4)+1(1)(y^5)
\\\\\\
32x^5+80x^4y+80x^3y^2+40x^2y^3+10xy^4+y^5

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

first find 10% of the original cost

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3 years ago
Need help please with this question
SashulF [63]

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5/8

5/8

Step-by-step explanation:

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3 years ago
Help don’t understand
marusya05 [52]

Answer:

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This is because when x is -4, y is 6, as seen in the graph

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This is because when x is 12, y is 6, as seen in the graph

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This is because when x is 0, y is -3, as seen in the graph

is f(4) positive or negative?
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