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3 years ago

13

Algebra II Help??? Subtracting Fractions (2x)/(y^2-x^2) - (x)/(y-x)

1 answer:

denis23 [38]3 years ago

4 0

Make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
$\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}$ =
$\frac{2x-x(x+y)}{y^2-x^2}$ =
$\frac{2x-x^2-xy}{y^2-x^2}$

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<u><em>Answer:</em></u>

A. $4397.9

<u><em>Explanation:</em></u>

We are given that Kendra sold 200 shares and that the price per share was $22.1

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Option A

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<u>Solution:</u>

Given that we have to write $y = \frac{1}{6}x+7$ in standard form

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In this kind of equation, x and y are variables and A, B, and C are integers

Given equation is:

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