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Reptile [31]
3 years ago
13

Algebra II Help??? Subtracting Fractions (2x)/(y^2-x^2) - (x)/(y-x)

Mathematics
1 answer:
denis23 [38]3 years ago
4 0
Make bottom number same

ok, so remember
(a-b)(a+b)=a²+b²
so

to get from (y-x) to (y²-x²), multiply 2nd fraction by (y+x)

so multiply 2nd fraction by (y+x)/(y+x)
\frac{2x}{y^2-x^2}- \frac{(y+x)(x)}{y^2-x^2}=
\frac{2x-x(x+y)}{y^2-x^2}=
\frac{2x-x^2-xy}{y^2-x^2}
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