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lora16 [44]
3 years ago
12

a ferris wheel can accommodate 65 people in 25 minutes. How many people could ride the ferris wheel in 3 hours. what is the rate

per hour?
Mathematics
1 answer:
MariettaO [177]3 years ago
6 0

25/60 = 0.42 hours

65/0.42 = 156 people per hour

156 *3 = 468 people in 3 hours

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Borrow money from a relative, use credit cards to build up good credit, do a fundraiser. This is what you could do to pay off debts
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Steven wants to increase the number of books he reads per year. He currently reads 2 books a year. He wants to triple the number
Sladkaya [172]

Answer:

B=2\times 3^n

Step-by-step explanation:

<u>Exponential Growing </u>

Steven currently reads 2 books a year. He wants to triple the number of books read per year. The first year he should read

2*3 = 6\ books

By the second year, he should read

2*3^2 = 18\ books

By the third year, he should read

2*3^3 = 54\ books

We can clearly see there is a geometric progression of the number of books he should read for the year n. The general formula is, being B the number of books read at the year n

\boxed{B=2\times 3^n}

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3 years ago
Please help with algebra
gregori [183]

Answer:

54%

Step-by-step explanation:

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2 years ago
The mean per capita income is 16,127 dollars per annum with a variance of 682,276. What is the probability that the sample mean
MakcuM [25]

Answer:

0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation, which is also called standard error s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

The standard deviation is the square root of the variance. So

\mu = 16127, \sigma = \sqrt{682276} = 826, n = 476, s = \frac{826}{\sqrt{476}} = 37.86

What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

Either it differs by 104 or less dollars, or it differs by more than 104 dollars. The sum of the probabilities of these events is 100. I am going to find the probability that it differs by 104 or less dollars first.

Probability that it differs by 104 or less dollars first.

pvalue of Z when X = 16127 + 104 = 16231 subtracted by the pvalue of Z when X = 16127 - 104 = 16023. So

X = 16231

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{16231 - 16127}{37.86}

Z = 2.75

Z = 2.75 has a pvalue of 0.9970

X = 16023

Z = \frac{X - \mu}{s}

Z = \frac{16023 - 16127}{37.86}

Z = -2.75

Z = -2.75 has a pvalue of 0.0030

0.9970 - 0.0030 = 0.9940

99.40% probability that it differs by 104 or less.

What is the probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

p + 99.40 = 100

p = 0.60

0.60% probability that the sample mean would differ from the true mean by more than 104 dollars if a sample of 476 persons is randomly selected

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3 years ago
What is 5 + 72?<br><br> a 81<br> b 72<br> c 5<br> d 62
maxonik [38]

The answer is 77 but i don't see it as an option here ;/

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