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Jobisdone [24]
2 years ago
15

Please help me for my mathematics class, thank you

Mathematics
2 answers:
Murljashka [212]2 years ago
7 0
Ohh god you can actually ask yung class that cheat cheat
Bess [88]2 years ago
6 0
Ahh that’s a lot of work to do. Sry bud
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HELPP PLISS
Otrada [13]

Answer:

C. Tan

Step-by-step explanation:

This is because you are given the measure of the opposite angle and the adjacent side.

7 0
3 years ago
Solve for x. Enter the solutions from least to greatest.
shepuryov [24]

Answer:

Lesser = -7

Greater = 4

7 0
2 years ago
-6(-4x + 3) = 2(10x + 3)
Naya [18.7K]

Answer:

x = -6/11

Step-by-step explanation:

-6(-4x + 3) = 2(10x + 3)

-6 * -4x = -24x

-6 * 3 = -18

2 * 10x = 20x

2 * 3 = 6

-24x - 18 = 20x + 6

-20x           -20x

-44x - 18 = 6

+18           +18

-44x = 24

-------   ------

 -44      -44

24/-44 = -24/44

-24/44 = -6/22

x = -6/11

8 0
3 years ago
A deli made $320,000 in revenue last year. Due to increased popularity of the deli, the owner predicts that revenue will increas
DedPeter [7]

Answer:  $736.000

Step-by-step explanation:

if u take out the 4 0s in 320.000 u will get 32 if u take out the percent of 23% u get 23 now mutiply 32 and 23 now u get 736 now add 3 0s then you have your answer

4 0
3 years ago
Explain why a quadratic equation with a positive discriminant has two real solutions, a quadratic equation with a negative discr
Bad White [126]

Answer:

A quadratic equation can be written as:

a*x^2 + b*x + c = 0.

where a, b and c are real numbers.

The solutions of this equation can be found by the equation:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

Where the determinant is D = b^2 - 4*a*c.

Now, if D>0

we have the square root of a positive number, which will be equal to a real number.

√D = R

then the solutions are:

x = \frac{-b +- R }{2*a}

Where each sign of R is a different solution for the equation.

If D< 0, we have the square root of a negative number, then we have a complex component:

√D = i*R

x = \frac{-b +- C*i }{2*a}

We have two complex solutions.

If D = 0

√0 = 0

then:

x = \frac{-b +- 0}{2*a} = \frac{-b}{2a}

We have only one real solution (or two equal solutions, depending on how you see it)

3 0
3 years ago
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