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3 years ago

13

One characteristic of all linear functions is that they will change by

1 answer:

ElenaW [278]3 years ago

3 0

The same constant value(s)

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Help me i hate word problems

VMariaS [17]

Is that all? My Algebra is freackin hard compared to this. Anyways, The way I understand this, is that we will have 3 (liters of water) +0.5 (half a liter of lemonade) =3.5 liters of liquid

so the question would be: how many times does fit into 3.5?

if you want to divide by a fraction, you need to multiply by the reverse of it.

so the answer is: 10 servings of lemonade ( and a little bit will be left over for half a serving).
Hope this helps!

4 0

2 years ago

Find the value of :<br><img src="https://tex.z-dn.net/?f=%20%5Csf%20log_%7B3%20%5Csqrt%7B2%7D%20%7D%28324%29%20" id="TexFormula1

qwelly [4]

Answer:

4

Step-by-step explanation:

Is that a log with the base of 3√(2) ?

If so....my calculator says the answer is 4

Let's see if we can do it w/ou the calculator:

3 sqrt(2)^x = 324 = 3^4 * 2^2 Now 'LOG' both sides:

x log (3 sqrt 2) = log (3^4 *2^2) = 4 log ( 3 * 2^(2/4)) = 4 log (3 sqrt2)

now divide both sides by log (3 sqrt2 )

x = 4 (If I did the math correctly ! )

8 0

2 years ago

Which term describes the variable y in the expression yn?<br> A.Product B.Factor C.Base D.Exponent

grigory [225]

If the expression is: yⁿ
then y is the Base.

If the expression is: yn
then y is the product.

5 0

2 years ago

Can anyone help me out with question 6. ASAP prefer teachers but if you know let me know thx!

SVETLANKA909090 [29]

You can take in x values starting from -4 to 4. Substitute the x values in the equation and find the y values.

Using the values, you can plot the line.

Easy :)

7 0

3 years ago

HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid

Harlamova29_29 [7]

Answer: Missing parts are,

In first blank, $AD\cong DC$ ,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

$\angle BDA\cong \angle BDC$ ( right angles )

$BD\cong BD$ ( reflexive)

Thus, By SAS ( side angle side )postulate,

$\triangle ADB\cong \triangle CDB$

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

$AB\cong CB$

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.

7 0

2 years ago

Read 2 more answers