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ikadub [295]
3 years ago
14

Find the missing value so that the line passing through the points has the given slope.

Mathematics
1 answer:
galben [10]3 years ago
7 0

Answer:

11

Step-by-step explanation:

4-1=3/11-7=4

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The rational number 5 3/7 is equal to <br><br><br> is equal to
Andrei [34K]

Answer:

38/7 is = to 5 3/7

Step-by-step explanation:

7 0
3 years ago
What is the predicted difference in sleep between individuals A and B, where individual A has 12 years of education and works 20
kari74 [83]

Answer: The predicted difference in sleep is 1251437 minutes.

Step-by-step explanation:

Since we have given that

Number of years of education = 12 years

Number of minutes a week = 2000

As we have

In case of individual A:

7 days = 2000 minutes

1 year = 365 days = \dfrac{2000}{7}\times 365=104285

12 years = 104285\times 12=1251420\ minutes

In case of individual B:

7 days = 3000 minutes

1 year = 365 days = \dfrac{3000}{7}\times 365=156428

16 years = 156428\times 16=2502857 minutes

So, the predicted difference in sleep between individuals A and B is given by

2502857-1251420\\\\=1251437\ minutes

Hence, the predicted difference in sleep is 1251437 minutes.

7 0
3 years ago
A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei
Arte-miy333 [17]

Answer:

<em>Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom</em>

<em>The null hypothesis is accepted . </em>

<em>Assume the population variances are approximately the same</em>

<u><em>Step-by-step explanation:</em></u>

<u>Explanation</u>:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

<em>The first sample size  'n₁'= 20</em>

<em>mean of the first sample 'x₁⁻'= 17.53 pounds</em>

<em>standard deviation of first sample  S₁ = 3.2 pounds</em>

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

<em>The second sample size  n₂ = 24</em>

<em>mean of the second sample  "x₂⁻"= 14.89 pounds</em>

<em>standard deviation of second sample  S₂ =  2.7 poun</em>ds

<u><em>Null hypothesis</em></u><u>:-</u><u><em>H₀</em></u><em>: The Population Variance are approximately same</em>

<u><em>Alternatively hypothesis</em></u><em>: H₁:The Population Variance are approximately same</em>

<em>Level of significance ∝ =0.05</em>

<em>Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42</em>

<em>Test statistic :-</em>

<em>    </em>t = \frac{x^{-} _{1} -  x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} }  }

<em>    where         </em>S^{2}   = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2}   }{n_{1} +n_{2} -2}

                      S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}

<em>              substitute values and we get  S² =  40.988</em>

<em>     </em>t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24}  )}<em></em>

<em>  </em>   t =  1.3622

  Calculated value t = 1.3622

Tabulated value 't' =  2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

<u><em>Conclusion</em></u>:-

<em>The null hypothesis is accepted </em>

<em>Assume the population variances are approximately the same.</em>

<em>      </em>

<em>                        </em>

<em>                    </em>

6 0
3 years ago
If h(x)=(x-2)^2, find h(x+1)
Softa [21]

Answer:

Step-by-step explanation:

h(x+1) = ( x + 1 - 2)²

= (x -1)²

8 0
3 years ago
In triangle abc, the angle c is six times as large as angle
mote1985 [20]
The interior angles of a triangle add up to 180 degrees

a = 1st angle, b = 2nd angle, c = 3rd angle

c = 6a
b = a + 60
a + b + c = 180

a + (a + 60) + (6a) = 180
8a + 60 = 180
8a = 180 - 60
8a = 120
a = 120/8
a = 15 <=== here is one angle

b = a + 60
b = 15 + 60
b = 75 <=== and another one

c = 6a
c = 6(15)
c = 90 <=== and the last angle

3 0
3 years ago
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