De Moivre's theorem uses this general formula z = r(cos α + i<span> sin α) that is where we can have the form a + bi. If the given is raised to a certain number, then the r is raised to the same number while the angles are being multiplied by that number.
For 1) </span>[3cos(27))+isin(27)]^5 we first apply the concept I mentioned above where it becomes
[3^5cos(27*5))+isin(27*5)] and then after simplifying we get, [243 (cos (135) + isin (135))]
it is then further simplified to 243 (-1/ √2) + 243i (1/√2) = -243/√2 + 243/<span>√2 i
and that is the answer.
For 2) </span>[2(cos(40))+isin(40)]^6, we apply the same steps in 1)
[2^6(cos(40*6))+isin(40*6)],
[64(cos(240))+isin(240)] = 64 (-1/2) + 64i (-√3 /2)
And the answer is -32 -32 √3 i
Summary:
1) -243/√2 + 243/√2 i
2)-32 -32 √3 i
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brainly.com/question/1285899
#SPJ4
Answer:
sorry the equation is confusing
Step-by-step explanation:
and pls fix it and thx.
Answer:
{1, 5, 25, 125, 625}
Step-by-step explanation:
The smallest positive integers that meet the requirement will be ...
5^0 = 1
5^1 = 5
5^2 = 25
5^3 = 125
5^4 = 625
As a set, these numbers are {1, 5, 25, 125, 625}.
Answer:
(0,27)
Step-by-step explanation:
x2 + 27 = 0
Solutions based on quadratic formula:
x1
= −0 − √ 02 − 4×1×27
2×1
= 0 − 6 × √ 3 i
2
≈ −5.196152i
x2
= −0 + √ 02 − 4×1×27
2×1
= 0 + 6 × √ 3 i 2
≈ 5.196152i
Extrema:
Min = (0, 27)