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victus00 [196]
3 years ago
14

V + 2 > - 19 I need help solving​

Mathematics
1 answer:
sammy [17]3 years ago
6 0

Answer:

first figure out what v is then add it with 2 then compare

Step-by-step explanation:

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Please solve the problem with steps
Debora [2.8K]

Answer:

Infinite series equals 4/5

Step-by-step explanation:

Notice that the series can be written as a combination of two geometric series, that can be found independently:

\frac{3^{n-1}-1}{6^{n-1}} =\frac{3^{n-1}}{6^{n-1}} -\frac{1}{6^{n-1}} =(\frac{1}{2})^{n-1} -\frac{1}{6^{n-1}}

The first one: (\frac{1}{2})^{n-1} is a geometric sequence of first term (a_1) "1" and common ratio (r) " \frac{1}{2} ", so since the common ratio is smaller than one, we can find an answer for the infinite addition of its terms, given by: Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{2} } =\frac{1}{\frac{1}{2} } =2

The second one: \frac{1}{6^{n-1}} is a geometric sequence of first term "1", and common ratio (r) " \frac{1}{6} ". Again, since the common ratio is smaller than one, we can find its infinite sum:

Infinite\,Sum=\frac{a_1}{1-r} = \frac{1}{1-\frac{1}{6} } =\frac{1}{\frac{5}{6} } =\frac{6}{5}

now we simply combine the results making sure we do the indicated difference: Infinite total sum= 2-\frac{6}{5} =\frac{10-6}{5} =\frac{4}{5}

8 0
3 years ago
Read 2 more answers
Which graph represents a function that is decreasing at a nonconstant rate?
Tasya [4]

Answer: C

since the line isn't straight, the slope/function is decreasing but not at a constant rate

3 0
3 years ago
I need help with this.....skdkdidennebdndjdhdvevdhd
MAXImum [283]
The answer is c......
6 0
3 years ago
Does (-2)^n/( 3^n+1) converge or diverge?
hodyreva [135]
\left|\dfrac{(-2)^n}{3^n+1}\right|=\dfrac{2^n}{3^n+1}

As n\to\infty, the sequence a_n=\left(\dfrac23\right)^n converges to zero.

If you're talking about the infinite series

\displaystyle\sum_{n\ge0}\dfrac{(-2)^n}{3^n+1}

well we've shown by comparison that this series must also converge because we know any geometric series \sum\limits_n r^n will converge as long as |r|.
3 0
3 years ago
Y=-2<br><img src="https://tex.z-dn.net/?f=y%20%3D%20%20-%202%20%5C%5C%204x%20-%203y%20%3D%2018" id="TexFormula1" title="y = - 2
Morgarella [4.7K]
I think is
4x - 3 (-2) = 18
4x + 6 = 18
4x = 12
x = 3
5 0
3 years ago
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