Answer:
LHS.= Sin 2x /( 1 + cos2x )
We have , sin 2x = 2 sinx•cosx
And. cos2x = 2cos^2 x - 1
i.e . 1+ cosx 2x = 2cos^2x
Putting the above results in the LHSwe get,
Sin2x/ ( 1+ cos2x ) =2 sinx•cosx/2cos^2x
=sinx / cosx
= Tanx
.•. sin2x/(1 + cos2x)= tanx
Step-by-step explanation:
Answer:
A ≈ 35.3 units²
Step-by-step explanation:
Calculate the radius CB using Pythagoras' identity in the right triangle.
CB² + AB² = AC²
CB² + 6² = 9²
CB² + 36 = 81 ( subtract 36 from both sides )
CB² = 45 = r²
Then area of quarter circle is
A =
× πr² =
× π × 45 ≈ 35.3
Y=9.25 because inorder to solve this we need to first take 5*.3 which equals 1.5 now that we have this we can move on we now have the equation 1.5 + 2y = 20 so now we need to continue working on getting y by it self so we subtract 1.5 from each side and then that leaves us with 2y=18.5 now we divide by 2 which leaves us with y=9.25 enjoy=)
Answer:
x = 76.9
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp side / adj side
tan 70 = x/28
28 tan 70 = x
x=76.92936
Rounding to the nearest tenth
x = 76.9
Answer:
33 1/3 lb
Step-by-step explanation:
When the distance between them goes from 8 ft to 12 ft, it is 1.5 times what it was. Then the force will be multiplied by the inverse of the square of this:
(75 lb)×1/(1.5²) = 75/2.25 lb = 33 1/3 lb
At 12 feet apart, the attraction force is 33 1/3 pounds.