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kogti [31]
3 years ago
6

For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th

ey are bijective.No justification needed.The firstthree have already been filled out for you, as an example. Also, recall interval notation:[a,b] ={x∈R:a≤xandx≤b}. You should be able to come up with a similar definitionfor (a,b) and (a,b] and [a,b).1.f:R→R, f(x) =x2.f:R≥0→R, f(x) =x+ 13.f:R≥0→R, f(x) = cos(x)4.f:R→R, f(x) =ex5.f:R→R, f(x) =2xifx≥0−x2ifx <0.6.f:R→(0,[infinity]), f(x) =ex7.f:R≥0→R≥0, f(x) =x48.f:{−1,2,−3}→{1,4,9}, f(x) =x29.f:R≥0→[−1,1], f(x) = cos(x)10.f: [0,π]→[−1,1], f(x) = cos(x)11.f:R≥0→[−1,1], f(x) = 012.f: US Citizens→Z, f(x) = the SSN ofx.13.f: US Zip Codes→US States, f(x) = The state thatxbelongs to.

Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

(a,b)=\left \{ x\in\Re : a

2. Functions

1) \Re \rightarrow \Re \\ f(x)=x

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2)\Re\geq0\rightarrow\Re , f(x)=x+1\\

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3)f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)

The cosine function is not injective, bijective nor surjective.

4)f:\Re\rightarrow\Re \:f(x)=ex

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5)  Quite unclear format

6) \:f:\Re\rightarrow(0,\infty), f(x) =ex

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

7) f:\Re\geq 0 \rightarrow  \Re\geq0, f(x) =x^{4}

Not injective nor surjective therefore not bijective too.

8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}

f(-1)=1, f(2)=4, f(-3)=9

Injective (one to one), Surjective,  and Bijective.

10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.

Surjective.

11.f:R\geq 0[-1,1], f(x) = 0\\

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

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Step-by-step explanation:

Let the length = L

Let the width = W

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Factor completely 50a2b5 − 35a4b3 + 5a3b4
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The complete factorisation of 50a²b⁵ − 35a⁴b³ + 5a³b⁴ is 5a²b³(10b² - 7a² + ab)

<h3>How to factorise?</h3>

Factorisation is the process of writing an expression as a product of two or more common factors.

The expression is written as a product of several factor.

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