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3 years ago

5

How do you work this out?

2 answers:

kondaur [170]3 years ago

5 0

2 hours. because there was little work

Ira Lisetskai [31]3 years ago

3 0

I'm guessing you find the length of the hypotenuse using the pythagorean theorem.

a² + b² = c² a and b are the legs and c is the hypotenuse

15² + 8² = c²

225 + 64 = c²

289 = c²

√289 = √c²

17 = c

hope that helps, God bless!

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The hypotenuse of a right triangle is twice the length of one of its legs. The length of the other leg is three feet. Find the l

kari74 [83]

Answer:

2√3 = hypotenuse

√3 = side

Step-by-step explanation:

$\sqrt{3^{2} +x^{2} } = 2x \\\sqrt{9 +x^{2} } = 2x\\9+x^{2} =(2x)^{2} \\9+x^{2} = 4x^{2} \\9 = 4x^{2} - x^{2} = 3x^{2} \\3 = x^{2}\\\sqrt{3} = x\\\\2x = 2\sqrt{3}\\$

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2 years ago

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I had $3.00. My Mom gave $10.00. My Dad gave $30.00. My Aunt and Uncle gave me $100.00. I had another $7.00. How much did I have

zaharov [31]

Answer:

$150

Step-by-step explanation:

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have a great day :)

8 0

2 years ago

Please help. I don’t know what to do

fomenos

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v+29 = 73

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Using mathematical induction prove whether or not the following statement is true for all positive integers n, or show why it is

aniked [119]

Base case: For $n=1$ , the left side is 2 and the right is $2\cdot1^2=2$ , so the base case holds.

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We want to show that this implies truth for $n=k+1$ , that

$2+6+10+\cdots+4k-2+4(k+1)-2=2(k+1)^2$

The first $k$ terms on the left reduce according to the assumption above, and we can simplify the $k+1$ -th term a bit:

$\underbrace{2+6+10+\cdots+4k-2}_{2k^2}+4k+2$

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3 years ago

What do you notice about subtracting 0 from an integer? Why does this make sense?

madam [21]

When you subtract an integer from 0 it is a negative number

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2 years ago