Y=2
Since the table (y) increase by 2 each time the answer would be y=2
Part a: subtract 48-30=18
Part b: i found it by subtracting 48 -30 because it says left over
a+b+c=0
[(a+b+c)^2=a^2+b^2+c^2+2ab+2ac+2bc]
[a^2+b^2+c^2+2ab+2ac+2bc=0]
[a^2+b^2+c^2=-(2ab+2ac+2bc)]
[a^2+b^2+c^2=-2(ab+ac+bc)] (i)
also
[a=-b-c]
[a^2=-ab-ac] (ii)
[-c=a+b]
[-bc=ab+b^2] (iii)
adding (ii) and (iii) ,we have
[a^2-bc=b^2-ac] (iv)
devide (i) by (iv)
[(a^2+b^2+c^2)/(a^2-bc)=(-2(ab+bc+ca))/(b^2-ac)]
Answer:
5/9
Step-by-step explanation:
The given is students that failed the test. 5 students completed the homework and failed the test and there is a total of 9 students who failed the test. So, the answer would be 5/9