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Tcecarenko [31]

3 years ago

12

The probability that John receives junk mail is 11 percent. If he receives 94 pieces of mail in a week, about how many of them c

an he expect to be junk mail?
Group of answer choices

1 answer:

SVETLANKA909090 [29]3 years ago

5 0

Answer:

10 (10.34 rounded down)

Step-by-step explanation:

11% is the same as .11

Multiply by 94 for your answer.

.11 x 94 = 10.34

10 pieces

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Which property should Remus use to solve the equation below? 7 q = 49 division property of equality addition property of equalit

AysviL [449]

The division property of equality should Remus used to solve the given equation and this can be determined by using the given data.

Given :

Equation is $7q = 49$ .

The following steps can be used in order to determine the property that Remus use to solve the given equation:

Step 1 - Write the given equation.

$7q = 49$

Step 2 - The arithmetic operations can be used in order to evaluate the given equation.

Step 3 - Using the division property of equality the value of 'q' can be determined.

$q = \dfrac{49}{7}$

$q = 7$

Therefore, the correct option is A).

For more information, refer to the link given below:

brainly.com/question/11897796

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2 years ago

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Imagine now that you put your hand in the refrigerator and pull out a piece of fruit.

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4 years ago

When he was little, Miguel could not sleep without his Captain Terrific action figure. It looked so life-like because it was a p

krok68 [10]

The answer is:
216×0.93÷10=20.088

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3 years ago

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Leno4ka [110]

Answer:

$\frac{s^2-25}{(s^2+25)^2}$

Step-by-step explanation:

Let's use the definition of the Laplace transform and the identity given: $\mathcal{L}[t \cos 5t]=(-1)F'(s)$ with $F(s)=\mathcal{L}[\cos 5t]$ .

Now, $F(s)=\int_0 ^{+ \infty}e^{-st}\cos(5t) dt$ . Using integration by parts with u=e^(-st) and dv=cos(5t), we obtain that $F(s)=\frac{1}{5}\sin(5t)e^{-st} |_{0}^{+\infty}+\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt=\int_0 ^{+ \infty}e^{-st}\sin(5t) dt$ .

Using integration by parts again with u=e^(-st) and dv=sin(5t), we obtain that

$F(s)=\frac{s}{5}(\frac{-1}{5}\cos(5t)e^{-st} |_{0}^{+\infty}-\frac{s}{5}\int_0 ^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}(\frac{1}{5}-\frac{s}{5}\int_0^{+ \infty}e^{-st}\sin(5t) dt)=\frac{s}{5}-\frac{s^2}{25}F(s)$ .

Solving for F(s) on the last equation, $F(s)=\frac{s}{s^2+25}$ , then the Laplace transform we were searching is $-F'(s)=\frac{s^2-25}{(s^2+25)^2}$

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Law Incorporation [45]

Answer:

50x50=1000000

Step-by-step explanation:

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3 years ago