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2 years ago

8.6 x10^-9 in standard form

Mathematics

1 answer:

katen-ka-za [31]2 years ago

4 0

-9 in power means that the value is in fractional and the 10 base is multipied 9 times and put it on denominator.

8.6 = 86 x 10^-1

Let's multiply :

86 x 10^-1 x 10^-9

= 86 x 10^-10

= 86/10000000000

=0,0000000086

Note : if you don't know about how 10^-1 x 10^-9 returns 10^-10, it's because of exponential rules. If the base are same wuth each other, then just do the addition operation in the exponent like this :

10^(-1+(-9))

= 10^(-1-9)

=10^-10

Hope it helps :)

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Write the equation of the line that has a slope of -4 and goes through (3,-3)

Sindrei [870]

The functional equation of the line is f (x)=a*x+b
you have already a: -4 -->f (x)=-4 x+b
Now you can use the point (3;-3)
3 is the x-coordinate and -3 the f (x)-coordinate
--> -3 = -4*(3) + b Now you can solve it
-3 = -12+b (+12)
b = 9
ANSWER: f (x) = -4x + 9

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2 years ago

Write the numbers 57,000,000,000 and 19,000 in scientific notation. Then show how to divide 57,000,000,000 by 19,000 using prope

LenaWriter [7]

Answer:

the first number is 57 to the ninth power and the second is 19 to the third power, not to sure about the dividing but a quick google search should do the trick

Step-by-step explanation:

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2 years ago

Which list of ordered pairs does NOT represent a function? A.(8, 80), (6, 80), (3, 80), (7, 80), (5, 80) B. (7, 80), (6, 60), (5

olga_2 [115]

Answer:

Step-by-step explanation:

Because they want you to see the number who is repeating like 80 in the later A is 4 times repeated. I hope it help

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2 years ago

Type the correct answer in each box. Use numerals instead of words.

lubasha [3.4K]

Answer:

System A has 4 real solutions.

System B has 0 real solutions.

System C has 2 real solutions

Step-by-step explanation:

System A:

x^2 + y^2 = 17 eq(1)

y = -1/2x eq(2)

Putting value of y in eq(1)

x^2 +(-1/2x)^2 = 17

x^2 + 1/4x^2 = 17

5x^2/4 -17 =0

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a = 5/4, b =0 and c = -17

$x=\frac{-(0)\pm\sqrt{(0)^2-4(5/4)(-17)}}{2(5/4)}\\x=\frac{0\pm\sqrt{85}}{5/2}\\x=\frac{\pm\sqrt{85}}{5/2}\\x=\frac{\pm2\sqrt{85}}{5}$

Finding value of y:

y = -1/2x

$y=-1/2(\frac{\pm2\sqrt{85}}{5})$

$y=\frac{\pm\sqrt{85}}{5}$

System A has 4 real solutions.

System B

y = x^2 -7x + 10 eq(1)

y = -6x + 5 eq(2)

Putting value of y of eq(2) in eq(1)

-6x + 5 = x^2 -7x + 10

=> x^2 -7x +6x +10 -5 = 0

x^2 -x +5 = 0

Using quadratic formula:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

a= 1, b =-1 and c =5

$x=\frac{-(-1)\pm\sqrt{(-1)^2-4(1)(5)}}{2(1)}\\x=\frac{1\pm\sqrt{1-20}}{2}\\x=\frac{1\pm\sqrt{-19}}{2}\\x=\frac{1\pm\sqrt{19}i}{2}$

Finding value of y:

y = -6x + 5

y = -6(\frac{1\pm\sqrt{19}i}{2})+5

Since terms containing i are complex numbers, so System B has no real solutions.

System B has 0 real solutions.

System C

y = -2x^2 + 9 eq(1)

8x - y = -17 eq(2)

Putting value of y in eq(2)

8x - (-2x^2+9) = -17

8x +2x^2-9 +17 = 0

2x^2 + 8x + 8 = 0

2x^2 +4x + 4x + 8 = 0

2x (x+2) +4 (x+2) = 0

(x+2)(2x+4) =0

x+2 = 0 and 2x + 4 =0

x = -2 and 2x = -4

x =-2 and x = -2

So, x = -2

Now, finding value of y:

8x - y = -17

8(-2) - y = -17

-16 -y = -17

-y = -17 + 16

-y = -1

y = 1

So, x= -2 and y = 1

System C has 2 real solutions

4 0

2 years ago

Read 2 more answers

1, 3,4,5,11, answer is 65 _ + (_-_)^2 +_x_

Y_Kistochka [10]

Answer:

1 + (11-4)^2 +3x5

Step-by-step explanation:

1 + (11-4)^2 +3x5

1 + (7)^2 + 3 x 5

1 + 49 + 15

50 + 15 = 65

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2 years ago