Answer:
y=10
Step-by-step explanation:
y/5+7=9
y/5=9-7
y/5=2
y=2*5
y=10
There are infinitely many solutions to this problem (which is why it asks what could those numbers be), so you just have to make one up!
Start with the first sentence.
x + y + z = 6.0
Now one of those numbers has to be less than 1. I'll choose x. And I'll choose a random number, say, 0.7.
0.7 + y + z = 6.0
Now I'll subtract 0.7 from both sides to see what y and z have to add up to.
0.7 + y + z - 0.7 = 6.0 - 0.7
y + z = 5.3
Now I'll choose a random number for y that's less than 5.3.
2.6 + z = 5.3
And subtract 2.6 from both sides to find z.
2.6 + z - 2.6 = 5.3 - 2.6
z = 2.7
And now we have our numbers!
x = <u>0.7</u>
y = <u>2.6</u>
z = <u>2.7</u>
<u>EXPLANATION</u><u>:</u>
Given that
sin θ = 1/2
We know that
sin 3θ = 3 sin θ - 4 sin³ θ
⇛sin 3θ = 3(1/2)-4(1/2)³
⇛sin 3θ = (3/2)-4(1/8)
⇛sin 3θ = (3/2)-(4/8)
⇛sin 3θ = (3/2)-(1/2)
⇛sin 3θ = (3-1)/2
⇛sin 3θ = 2/2
⇛sin 3θ = 1
and
cos 2θ = cos² θ - sin² θ
⇛cos 2θ = 1 - sin² θ - sin² θ
⇛cos 2θ = 1 - 2 sin² θ
Now,
cos 2θ = 1-2(1/2)²
⇛cos 2θ = 1-2(1/4)
⇛cos 2θ = 1-(2/4)
⇛cos 2θ = 1-(1/2)
⇛cos 2θ = (2-1)/2
⇛cos 2θ = 1/2
Now,
The value of sin 3θ /(1+cos 2θ
⇛1/{1+(1/2)}
⇛1/{(2+1)/2}
⇛1/(3/2)
⇛1×(2/3)
⇛(1×2)/3
⇛2/3
<u>Answer</u> : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.
<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> If sin Θ = 2/3 and tan Θ < 0, what is the value of cos Θ?
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if cos θ -sin θ =1, find θ cos θ +sin θ?
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Answer:
5x^2 ( x^2 -2)(x^2 +2)(x^2+2x+2)(x^2-2x+2)
Step-by-step explanation:
5x^10 − 80x^2
The greatest common factor is 5x^2
5x^2 ( x^8 - 16)
Rewriting the parentheses
5x^2 ( x^4 ^2 - 4^2)
We notice the difference of squares (a^2 -b^2) = (a-b)(a+b)
5x^2 ( x^4 -4)(x^4+4)
Again rewriting the first parentheses
5x^2 ( x^2 ^2 -2^2)(x^4+4)
5x^2 ( x^2 -2)(x^2 +2)(x^4+4)
The last term can be rewritten as(x^2+2x+2)(x^2-2x+2)
5x^2 ( x^2 -2)(x^2 +2)(x^2+2x+2)(x^2-2x+2)
It is the first option- 12 times one fourth the quotient of 6 and 2