Question

The letters that form the word ALGEBRA are placed in a bowl. What is the probability, as a percent, of choosing a letter other than "A" and then choosing an "A"?

Answer 1

Answer:

Step-by-step explanation:

There are 7 letters in algebra. Two of them are "A"

The probability of choosing "A" on the first try is $\frac{2}{7}$

Assuming you remove the letter after choosing it:

If you remove the A, then the second time around you have 6 letters with one of them being A

So, your chances of picking A is $\frac{1}{6}$

Multiply the probabilities together.

$\frac{2}{7} *\frac{1}{6} =\frac{2}{42} =\frac{1}{21}$

Assuming you don't remove the letter after choosing it:

You have the same probability again, $\frac{2}{7}$

Square the probability:

$(\frac{2}{7})^2 =\frac{4}{49}$