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goblinko [34]
4 years ago
10

Esther starts at one corner of a square field and walks 90 feet along one side to another corner of the field. She turns 90° and

walks 70 feet, and then walks straight back to where she started. What is the area of the part of the field she walked around?
a. 3150 ft²
b. 4900 ft²
c. 6300 ft²
d. 8100 ft²
Mathematics
1 answer:
erma4kov [3.2K]4 years ago
3 0
The three sides make a right triangle and you know the base (90) and the height (70)

A = 1/2 bh  or 1/2 x (70)x (90)=   3150 ft²
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A city park commission received a donation of playground equipment from a parents' organization. The area of the playground need
mr_godi [17]

Answer:

8w

Step-by-step explanation:

7 0
4 years ago
Use Stokes' Theorem to evaluate S curl F · dS. F(x, y, z) = x2 sin(z)i + y2j + xyk, S is the part of the paraboloid z = 9 − x2 −
Korolek [52]

The vector field

\vec F(x,y,z)=x^2\sin z\,\vec\imath+y^2\,\vec\jmath+xy\,\vec k

has curl

\nabla\times\vec F(x,y,z)=x\,\vec\imath+(x^2\cos z-y)\,\vec\jmath

Parameterize S by

\vec s(u,v)=x(u,v)\,\vec\imath+y(u,v)\,\vec\jmath+z(u,v)\,\vec k

where

\begin{cases}x(u,v)=u\cos v\\y(u,v)=u\sin v\\z(u,v)=(9-u^2)\end{cases}

with 0\le u\le3 and 0\le v\le2\pi.

Take the normal vector to S to be

\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k

Then by Stokes' theorem we have

\displaystyle\int_{\partial S}\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S

=\displaystyle\int_0^{2\pi}\int_0^3(\nabla\times\vec F)(\vec s(u,v))\cdot\left(\dfrac{\partial\vec s}{\partial u}\times\dfrac{\partial\vec s}{\partial v}\right)\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^3u^3(2u\cos^3v\sin(u^2-9)+\cos^3v\sin v+2u\sin^3v+\cos v\sin^3v)\,\mathrm du\,\mathrm dv

which has a value of 0, since each component integral is 0:

\displaystyle\int_0^{2\pi}\cos^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\sin v\cos^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\sin^3v\,\mathrm dv=0

\displaystyle\int_0^{2\pi}\cos v\sin^3v\,\mathrm dv=0

4 0
3 years ago
How many numbers are 10 units from 0 on the number line?
barxatty [35]

The <em><u>correct answer</u></em> is:

2

Explanation:

There are two directions from 0 on a number line, to the left and to the right.

Numbers to the left of 0 on a number line are negative numbers; numbers to the right of 0 on a number line are positive numbers.

The number 10 units to the left of 0 on a number line is -10, and the number 10 units to the right of 0 on a number line is 10; there are two answers.

3 0
4 years ago
Read 2 more answers
A person whose eye level is 15 feet above the ground is looking at a building. The angle of elevation to the top of the building
uysha [10]

Answer:

61.97 feets

Step-by-step explanation:

Using trigonometry :

Horizontal distance between the person and building,

Let distance = d

Tan 15 = 15 / d

0.2679491 * d = 15

d = 15 / 0.2679491

d = 55.980781

To obtain the height, h :

tan 40 = (h-15)/d

d = 55.98

h-15 = 55.98 (tan 40°)

h - 15 = 55.98 * 0.8390996

h - 15 = 46.972797

h = 46.972797 + 15

h = 61.972797

h = 61.97 feets

4 0
3 years ago
All seasons plumbing has two service trucks that frequently need repair. if the probability the first truck is available is .74,
faltersainse [42]
Availability of first truck probability P (1) = 0.74 
Availability of second truck probability P (2) = 0.57 
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So the probability of at least one available P (1 or 2) = P (1) + P (2) - P (1 and 2) = 0.74 + 0.57 - 0.46 = 0.85 
Now the probability of at neither available = 1 - P (1 or 2) = 1 – 0.85 = 0.15
7 0
3 years ago
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