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3 years ago

Grace is an hourly employee, and the line that models her total pay in dollars

Mathematics

2 answers:

tresset_1 [31]3 years ago

5 0

Answer: Hello mate!

if x is the amount of hours worked, 45 is the slope and the y intercept is 35.

A linear equation has the form of y = ax + b, where a is the slope and b is the y-intercept, then the equation that we have is:

y = 45*x + 35

this means that she wins $45 per hour, and has a plane amount of $35, indiferent of the amount of hours worked.

Then the correct answer is

C) Grace's wage is $45 an hour, and it appears that she received a signing bonus of $35.

morpeh [17]3 years ago

3 0

APEX confirmed

Answer:Grace's wage is $45 an hour, and it appears that she received a signing bonus of $35

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Describe the slope of the line<br><br> Find the slope.<br><br> m =

spin [16.1K]

Answer:

m = -3/5

Step-by-step explanation:

Since the line is going downwards towards the right, it is a negative slope.

We can use the points to solve for the slope.

m = -2 - 1 / 2 - (-3)

m = -2 - 1 / 2 + 3

m = -3/5

Therefore, the slope is -3/5.

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3 years ago

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains

AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

$f(x) = (1-p)^{x}p$

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

$\mu = \frac{1-p}{p}$

The standard deviation of the geometric distribution is given by the following formula:

$\sigma = \sqrt{\frac{1-p}{p^{2}}$

In this problem, we have that:

$p = 0.383$

$\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61$

$\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05$

(a) What is the probability that a drought lasts exactly 3 intervals?

This is $f(3)$

$f(x) = (1-p)^{x}p$

$f(3) = (1-0.383)^{3}*(0.383)$

$f(3) = 0.09$

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is $P = f(0) + f(1) + f(2) + f(3)$

$f(x) = (1-p)^{x}p$

$f(0) = (1-0.383)^{0}*(0.383) = 0.383$

$f(1) = (1-0.383)^{1}*(0.383) = 0.236$

$f(2) = (1-0.383)^{2}*(0.383) = 0.146$

Previously in this exercise, we found that $f(3) = 0.09$

$P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855$

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is $P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4)$ .

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

$P(X \leq 3) + P(X \geq 4) = 1$

$0.855 + P(X \geq 4) = 1$

$P(X \geq 4) = 0.145$

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

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3 years ago

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shtirl [24]

Answer: D

Step-by-step explanation:

A seems complicated and doesn’t make an sense while D is simple

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What is the factored form of the polynomal? x2-12x+27

lianna [129]

Answer:

The answer is $(x-9) (x-3)$ .

Step-by-step explanation:

This is because when you multiply them together you get

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When you add the like terms you get,

$x^{2} - 12x +27$

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Before Tax Price: $70.75

Sale Tax: 8.11% or $5.74

After Tax Price: $76.49

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3 years ago

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