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sweet [91]
3 years ago
7

Grace is an hourly employee, and the line that models her total pay in dollars

Mathematics
2 answers:
tresset_1 [31]3 years ago
5 0

Answer: Hello mate!

if x is the amount of hours worked, 45 is the slope and the y intercept is 35.

A linear equation has the form of y = ax + b, where a is the slope and b is the y-intercept, then the equation that we have is:

y = 45*x + 35

this means that she wins $45 per hour, and has a plane amount of $35, indiferent of the amount of hours worked.

Then the correct answer is

C) Grace's wage is $45 an hour, and it appears that she received a  signing bonus of $35.

morpeh [17]3 years ago
3 0

APEX confirmed

Answer:Grace's wage is $45 an hour, and it appears that she received a  signing bonus of $35

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Komok [63]
<span>Triangles exist:
</span>3 acute angles<span> 2 acute angles, 1 right angle
</span><span>2 acute angles, 1 obtuse angle
</span>
Triangles DON'T exist for:
<span>1 acute angle, 1 right angle, 1 obtuse angle
</span><span>1 acute angle, 2 obtuse angles</span>


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The route for one day of a charity bike ride covers 50 miles. Individual participants ride this distance at different average sp
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How many cubic feet are in a carton measuring 6 feet, 8 inches by 3 yards by 4.5 inches?
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Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere
Ket [755]

Answer:

e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...

\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n

Step-by-step explanation:

<u>Taylor series</u> expansions of f(x) at the point x = a

\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...

This expansion is valid only if \text{f}\:^{(n)}(a) exists and is finite for all n \in \mathbb{N}, and for values of x for which the infinite series converges.

\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1

\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...

\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If  $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}

\text{f}(x)=e^{4x} \implies \text{f}(1)=e^4

\text{f}\:'(x)=4e^{4x} \implies \text{f}\:'(1)=4e^4

\text{f}\:''(x)=16e^{4x} \implies \text{f}\:''(1)=16e^4

Substituting the values in the series expansion gives:

e^{4x}=e^4+4e^4(x-1)+\dfrac{16e^4}{2}(x-1)^2+...

Factoring out e⁴:

e^{4x}=e^4\left[1+4(x-1)+8}(x-1)^2+...\right]

<u>Taylor Series summation notation</u>:

\displaystyle \text{f}(x)=\sum^{\infty}_{n=0} \dfrac{\text{f}\:^{(n)}(a)}{n!}(x-a)^n

Therefore:

\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n

7 0
1 year ago
Y=-1/2x+10x what is the height of the arch at the turning point
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3 years ago
Solve for y.<br> py + qy = -4y + 8<br> y =
Elanso [62]

Answer:

y=8/(p+q+4)

Step-by-step explanation:

py+qy=-4y+8

Collect all terms containing y together

Py+qy+4y=8

Factor out y

y(p+q+4)=8

Divide both sides by (p+q+4)

y(p+q+4)/(p+q+4)=8/(p+q+4)

y=8/(p+q+4)

3 0
3 years ago
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