Question

Rationalize the denominator of square root of negative 36 over open parentheses 2 minus 3 i close parentheses plus open parentheses 3 plus 2 i

Answer 1

$\frac{ \sqrt{-36} }{(2 - 3 i )+( 3 + 2 i )}= \\ = \frac{6i}{5-i}* \frac{5+i}{5+i}= \\ = \frac{30i+6i ^{2} }{25-i ^{2} } = \frac{-6+30i}{25+1}= \\ = \frac{-6+30i}{26}=$
= - 3/13 + 15/13 i