2 years ago

Is x+4 a factor of P(x)=4x^2-4x+8?

Mathematics

1 answer:

mina [271]2 years ago

4 0

Answer:

(x^3-2x^2-4)*(x+2)

Step-by-step explanation:

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Factorise the following using the Difference of Two Squares or Perfect Squares rule: a) (2x-2)^2 - (x+4)^2 b) (3x+4) (3x-4)

emmainna [20.7K]

Answer:

Step-by-step explanation:

Hello, please consider the following.

$(2x-2)^2 - (x+4)^2 \\\\=(2x-2-(x+4))(2x-2+x+4)\\\\=(2x-2-x-4)(3x+2)\\\\=\boxed{(x-6)(3x+2)}$

$(3x+4) (3x-4)\\\\=(3x)^2-4^2\\\\=\boxed{9x^2-16}$

Thank you.

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3 years ago

Is x+4 a factor of P(x)=4x^2-4x+8?​

Is x+4 a factor of P(x)=4x^2-4x+8?