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3 years ago

−9(t−2)=4(t−15) Pleasee Help Mee

Mathematics

2 answers:

iragen [17]3 years ago

8 0

Answer:

T = - 6

Step-by-step explanation:

See image for explanation

Masteriza [31]3 years ago

7 0

Answer: t = 6

Step-by-step explanation:

Distribute -9 into (t-2) and distribute 4 into (t-15). -9t + 18 = 4t - 60.
Subtract 4t on both sides. -13t + 18 = -60
Subtract 18 on both sides. -13t = -78
Divide 13 on both sides. t = 6

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Read 2 more answers

MATH HELP!!! 100PTS!!!

Lostsunrise [7]

Answer:

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Step-by-step explanation:

Given functions:

$p(x)=2x-4$

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Solve for p(x) = r(x):

$\begin{aligned}p(x) & = r(x)\\\implies 2x-4 & = \dfrac{6x-1}{9x+1}\\(2x-4)(9x+1)&=6x-1\\18x^2+2x-36x-4&=6x-1\\18x^2-40x-3&=0\end{aligned}$

As the found quadratic equation cannot be factored, use the Quadratic Formula to solve for x:

Quadratic Formula

$x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0$

Therefore:

$a=18, \quad b=-40, \quad c=-3$

Substitute the values of a, b and c into the quadratic formula and solve for x:

$\begin{aligned}\implies x & =\dfrac{-(-40) \pm \sqrt{(-40)^2-4(18)(-3)} }{2(18)}\\\\& =\dfrac{40 \pm \sqrt{1816}}{36}\\\\& =\dfrac{40 \pm \sqrt{4 \cdot 454}}{36}\\\\& =\dfrac{40 \pm \sqrt{4}\sqrt{454}}{36}\\\\& =\dfrac{40 \pm2\sqrt{454}}{36}\\\\& =\dfrac{20 \pm\sqrt{454}}{18}\end{aligned}$

Therefore, the solutions are:

$x =\dfrac{20 +\sqrt{454}}{18}, \quad \dfrac{20 -\sqrt{454}}{18}$

Learn more about quadratic equations here:

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