Given the angle:
-660°
Let's find the coterminal angle from 0≤θ≤360.
To find the coterminal angle, in the interval given, let's keep adding 360 degrees to the angle until we get the angle in the interval,
We have:
Coterminal angle = -660 + 360 = -300 + 360 = 60°
Therefore, the coterminal angle is 60°.
Since 60 degrees is between 0 to 90 degrees, is is quadrant I.
60 degrees lie in Quadrant I.
Also since it is in quadrant I, the reference angle is still 60 degrees.
ANSWER:
The coterminal angle is 60°, which lies in quadrant I, with a reference angle of 60°
Answer:
3/9
Step-by-step explanation:
15/45
divide both sides by a factor of each number; I'll be using 5.
3/9
It didn't have to be 5, I could have used 3, but in that case It wouldn't have been it's simplest form and I would have to divide again by another factor.
Answer: -1x - 1
Step-by-step explanation:
2 -1x -3
2-3 = -1
-1x - 1
Answer:
x = -2
TU = 4
UB = 2
Step-by-step explanation:
you can add x^2 with 4x+10 and equate it to 6:
x^2 + 4x + 10 = 6
x^2 + 4x + 4
then u can use the roots formula : x = (-b ± √ (b2 - 4ac) )/2a
so it'll be x = {-4±[√16 - 4(4)]}/2
x= -2
then u can substitute it and find TU and UB
TU= (-2)^2 = 4
UB= 4(-2)+10 = 2
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Explanation:</h2><h2>
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Hello! Remember you have to write complete questions in order to get good and exact answers. Here you haven't provided any figure, so I'll assume m∠1 and m∠2 are complementary angles. Angles that add up to 90° are called complementary angles. In this case, we know m∠1 and want to know m∠2. Thus, we can establish the following formula:
m∠1 + m∠2 = 90°
Isolating m∠2:
m∠2 = 90° - m∠1
m∠2 = 90° - 64
m∠2 = 26°
