Answer:
Two solutions are found:
n=0 , n= 4 ....
Step-by-step explanation:
n^2-4n = 0
Take common from the given expression:
n(n-4)=0
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately;
n(n-4)=0
n = 0.
n-4 = 0.
Add 4 at both sides:
n-4+4 = 0+4
n = 4
Therefore two solutions are found:
n=0 , n= 4 ....
Associative means that you can move the parenthesis around the problem and still get the same answer. like (4+2)+3=4+(2+3)
first & sixth are the true
In the given system of equations, the value of x is 7.334 and the value of y is 7.714
<h3>Solving system of linear equations</h3>
From the question, we are to solve the given system of linear equations
The given system of linear equations is
3x + 7y = 76 ------------ (1)
9y + 5y = 108 ------------ (2)
From equation (2), solve for y
9y+ 5y = 108
14y = 108
y = 108/14
y = 7.714
Substitute the value of x into equation (1), to determine the value of x
3x + 7y = 76
3x + 7(7.714) = 76
3x + 53.998 = 76
Subtract 53.998 from both sides of the equation
3x + 53.998 - 53.998 = 76 - 53.998
3x = 22.002
Divide both sides of the equation by 3
3x/3 = 22.002/3
x = 7.334
Therefore,
x = 7.334 and y = 7.714
Learn more on Solving system of linear equations here: brainly.com/question/13729904
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Answer:
14
Step-by-step explanation:
7( 8 - 6 ) = 7 ( 2 ) = 14
Following PEMDAS, you would begin with solving within the ( ). So being that m = 8 you plug that in. Then subtract 6 from 8 which would then give you 2. The multiply 7 by 2, which gives you 14.
